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Nitella [24]
3 years ago
6

Solve for x: log5(3×-1)=2

Mathematics
1 answer:
Anarel [89]3 years ago
6 0
If 5 is the base, 3(x-1) is the argument:
3x-1=5²
3x=26
x=26/3

If 5 is with 3x-1, that is, if 5(3x-1) is the argument, and the base is 10:
5(3x-1)=10²
3x-1=20
3x=21
x=7
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Help help help help help
vitfil [10]

Answer:

B

Step-by-step explanation:

Remark

If we draw a line from F to T, we can make a couple of statements.

Call the center of the circle O

1. <FTE = 1/2 the central angle of <FOE. The size of <FOE is the same size as the minor arc. Since The minor arc = 60 degrees, then FTE = 30 degrees.

2. <GTF = 1/2 78 by the same reasoning used above.  GTF = 39 because that is 1/2 of 78.

So the answer to the size of <T = 39 + 30 = 69 which is B

There is a much simpler way of doing this.

The central angle of the two arcs is 78 + 60 = 138

The <GTE is 1/2 the central angle

<GTE = 1/2 * 138 = 69

3 0
3 years ago
2(x+4)= -5x+1<br> Some one please solve
NeX [460]

Let's solve your equation step-by-step.

2(x+4)=−5x+1

Step 1: Simplify both sides of the equation.

2(x+4)=−5x+1

(2)(x)+(2)(4)=−5x+1(Distribute)

2x+8=−5x+1

Step 2: Add 5x to both sides.

2x+8+5x=−5x+1+5x

7x+8=1

Step 3: Subtract 8 from both sides.

7x+8−8=1−8

7x=−7

Step 4: Divide both sides by 7.

7x

7

=

−7

7

x=−1

Answer:

x=−1

7 0
3 years ago
PLEASE ANSWER THIS!!! IF DO, YOU ARE SMART!
Ratling [72]

Answer:

33.64

Step-by-step explanation:

4 0
3 years ago
1.2/4.4 = 3/a what is a
bazaltina [42]
Simply cross multiply and simplify to get a = 11

Hope this helped!! xx
7 0
4 years ago
Read 2 more answers
Find intergral (e^xcos(3x)dx
ArbitrLikvidat [17]

Answer:

Hello,

Step-by-step explanation:

Here is an other method than classical:

I=\int {e^x*cos(3x)} \, dx =e^x*(k_1/cos(3x)+k_2*sin(3x) )\\\\Let's\ derivate:\\\\e^xcos(3x)=e^x(k1*cos(3x)+k_2*sin(3x))+e^x*(k_1*(-sin(3x))*3+k_2*cos(3x)*3)\\\\By\ identification:\\\\\left\{\begin{array}{ccc}k_1+3k_2&=&1\\-3k_1+k2&=&0\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}k_1&=&\dfrac{1}{10}\\k2&=&\dfrac{3}{10}\\\end{array}\right.\\\\\\\boxed{I=e^x(\dfrac{1}{10}*cos(3x)+\dfrac{3}{10}*sin(3x))}\\

8 0
2 years ago
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