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Nitella [24]
3 years ago
6

Solve for x: log5(3×-1)=2

Mathematics
1 answer:
Anarel [89]3 years ago
6 0
If 5 is the base, 3(x-1) is the argument:
3x-1=5²
3x=26
x=26/3

If 5 is with 3x-1, that is, if 5(3x-1) is the argument, and the base is 10:
5(3x-1)=10²
3x-1=20
3x=21
x=7
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3 years ago
Solve forn: -6(n-8) = 4(12-5n)+14n
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so you have

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