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4 years ago

In Antarctica, Vinson Massit is at an elevation of 16,864 feet. How far above sea level is Vinson Massit?

Mathematics

1 answer:

GarryVolchara [31]4 years ago

5 0

Answer: 16,864 feet

Step-by-step explanation: sea level is 0

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Find the length of side xx in simplest radical form with a rational denominator.

borishaifa [10]

Answer:

x = 3sqrt(2)/2

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

The two legs are equal, x

x^2 + x^2 = 3^2

2x^2 = 9

Divide each side by 2

x^2 = 9/2

Take the square root of each side

sqrt(x^2) = sqrt(9/2)

x = sqrt(9)/ sqrt(2)

x = 3 / sqrt(2)

x = 3 sqrt(2) / sqrt(2)*sqrt(2)

x = 3sqrt(2)/2

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3 years ago

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Can someone help me with this please? It's due today!!

Juliette [100K]

Answer:

in order so the line can pass through those point the equation has to be:

Y=6/3x+0

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3 years ago

Inverse notation f^-1 used In a pure mathematics problem is not always used when finding inverses of applied problems. Rather, t

solong [7]

Answer:

a) 75.4 kg

b) $h(W)=\frac{W+83}{2.2}$

Step-by-step explanation:

a) The ideal weight of a 6-foot (72 inches) male is given by simply applying h= 72 in to the expression:

$W(72) = 49+2.2(72-60)\\W(72) =75.4\ kg$

b) Expressing height as a function of weight:

$W(h)= 49+2.2(h-60)\\2.2h-132+49=W\\h(W)=\frac{W+83}{2.2}$

Verifying with W(h(W)):

$W(h(W))= 49+2.2(\frac{W+83}{2.2} -60)\\W(h(W))= 49-132+W+83\\W(h(W))=W$

Verifying with h(W(h):

$h(W(h))=\frac{(49+2.2(h-60))+83}{2.2}\\h(W(h))=\frac{(49+2.2h-132+83)}{2.2}\\h(W(h))=h$

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3 years ago

_____?? help ??______<br>and NO FILES OR LINKS

posledela

314 m is the correct answer.

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3 years ago

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I need help with this, please

kobusy [5.1K]

Answer:

hey ya

Step-by-step explanation:

the answer is option c

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3 years ago