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Sliva [168]
3 years ago
13

What is the solution to −1/4(d+1)<2

Mathematics
1 answer:
kogti [31]3 years ago
5 0

Answer:

d > -9

Step-by-step explanation:

-\dfrac{1}{4}(d + 1) < 2

First, multiply both sides by -4. You must also change the inequality sign since you are multiplying both sides by a negative number.

-4 \times \left(-\dfrac{1}{4}\right)(d + 1) > 2 \times (-4)

d + 1 > -8

Subtract 1 from both sides.

d + 1 - 1 > -8 - 1

d > -9

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9 sq. ft.
because 3x3=9 as its a square
8 0
3 years ago
Read 2 more answers
2 1/2t = 11<br>what is t​
docker41 [41]
2.5t = 11
Then you divide both sides by 2.5
t =11/2.5
t = 4.4
7 0
3 years ago
Please help 1-12!!!!
natima [27]

Answers:  

1. b = - 6  

2. z = -7.5  

3. c = 5  

4. s = -38  

5. w = 12  

6. m = -(12/7)  

7. k = 88

8. x = -10

9. t = -7.5

10. d = 0.3

11. "a" can be any value (Infinite solutions)

12. No solution for "n"

Solution:  

1. -7(b+16)=7(b-4)  

Dividing both sides of the equation by 7:  

-7(b+16)/7=7(b-4)/7  

-(b+16)=b-4  

-b-16=b-4  

-b-16+b+4=b-4+b+4  

-12=2b  

2b=-12  

2b/2=-12/2  

b=-6  

Checking the solution:  

-7(b+16)=7(b-4)  

-7(-6+16)=7(-6-4)  

-7(10)=7(-10)  

-70=-70 Ok  

2. 9-z=3z+39  

9-z+z-39=3z+39+z-39  

-30=4z  

4z=-30  

4z/4=-30/4  

z=-7.5  

Checking the solution:  

9-z=3z+39  

9-(-7.5)=3(-7.5)+39  

9+7.5=-22.5+39  

16.5=16.5 Ok.  

3. 12c-5c=4c+15  

7c=4c+15  

7c-4c=4c+15-4c  

3c=15  

3c/3=15/3  

c=5  

Checking the solution:  

12c-5c=4c+15  

12(5)-5(5)=4(5)+15  

60-25=20+15  

35=35 Ok  

4. 40-5s=-2(-1+3s)  

40-5s=(-2)(-1)+(-2)(3s)  

40-5s=2-6s  

40-5s-40+6s=2-6s-40+6s  

s=-38  

Checking the solution:  

40-5s=-2(-1+3s)  

40-5(-38)=-2(-1+3(-38))  

40+190=-2(-1-114)  

230=-2(-115)  

230=230 Ok  

5. 2.8w+5.3=3.3w-0.7  

2.8w+5.3-2.8w+0.7=3.3w-0.7-2.8w+0.7  

6=0.5w  

0.5w=6  

0.5w/0.5=6/0.5  

w=12  

Checking the solution:  

2.8w+5.3=3.3w-0.7  

2.8(12)+5.3=3.3(12)-0.7  

33.6+5.3=39.6-0.7  

38.9=38.9 Ok  

6. 4(m+9)=3(8-m)  

(4)(m)+(4)(9)=(3)(8)+(3)(-m)  

4m+36=24-3m  

4m+36-36+3m=24-3m-36+3m  

7m=-12  

7m/7=-12/7  

m=-12/7  

Checking the solution:  

4(m+9)=3(8-m)  

4(-12/7+9)=3(8-(-12/7))  

4(-12+7(9))/7=3(8+12/7)  

4(-12+63)/7=3(7(8)+12)/7  

4(51)/7=3(56+12)/7  

204/7=3(68)/7  

204/7=204/7 Ok  

7. (1/8)k+32=(1/2)k-1

(1/8)k+32-32-(1/2)k=(1/2)k-1-32-(1/2)k

(1/8-1/2)k=-33

[(1-4(1))/8]k=-33

[(1-4)/8]k=-33

[(-3)/8]k=-33

(-3/8)k=-33

(-1)(-3/8)k=(-1)(-33)

(3/8)k=33

k=8(33)/3

k=264/3

k=88

Checking the solution:

(1/8)k+32=(1/2)k-1

(1/8)(88)+32=(1/2)(88)-1

(1)(88)/8+32=(1)(88)/2-1

88/8+32=88/2-1

11+32=44-1

43=43 Ok

8.  (3/4)x-x=-(1/4)(2x+10)

Multiplying both sides of the equation by 4:

4(3/4)x-4x=-(4/4)(2x+10)

3x-4x=-1(2x+10)

-x=(-1)(2x)+(-1)(10)

-x=-2x-10

-x+2x=-2x-10+2x

x=-10

Checking the solution:

(3/4)x-x=-(1/4)(2x+10)

(3/4)(-10)-(-10)=-(1/4)(2(-10)+10)

-30/4+10=-(1/4)(-20+10)

-7.5+10=-(1/4)(-10)

2.5=10/4

2.5=2.5  Ok


9. 9(t+1)=5(t-4)-1

(9)(t)+(9)(1)=(5)(t)+(5)(-4)-1

9t+9=5t-20-1

9t+9=5t-21

9t+9-9-5t=5t-21-9-5t

4t=-30

4t/4=-30/4

t=-7.5

Checking the solution:

9(t+1)=5(t-4)-1

9(-7.5+1)=5(-7.5-4)-1

9(-6.5)=5(-11.5)-1

-58.5=-57.5-1

-58.5=-58.5   Ok


10. 3d+1.1=2.3-d

3d+1.1-1.1+d=2.3-d-1.1+d

4d=1.2

4d/4=1.2/4

d=0.3

Checking the solution:

3d+1.1=2.3-d

3(0.3)+1.1=2.3-0.3

0.9+1.1=2.0

2.0=2.0   Ok


11. -7(a+2)+15=1-7a

(-7)(a)+(-7)(2)+15=1-7a

-7a-14+15=1-7a

-7a+1=1-7a

-7a+1-1+7a=1-7a-1+7a

0=0

"a" can be any value (Infinite solutions)

Checking the solution: For example a=0

-7(a+2)+15=1-7a

-7(0+2)+15=1-7(0)

-7(2)+15=1-0

-14+15=1

1=1   Ok


12. 6(3n-1)=2(9n+4)

(6)(3n)+(6)(-1)=(2)(9n)+(2)(4)

18n-6=18n+8

18n-6+6-18n=18n+8+6-18n

0=14 It's not possible, because 0 is different to 14, then there is no solution for "n".

5 0
3 years ago
Read 2 more answers
Find the shortest distance from A to C in the diagram below.
Lapatulllka [165]

Answer:

The shortest distance from A to C is AC=5\sqrt{13}\ units

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shortest distance from A to C is the hypotenuse of the right triangle AYC

Applying the Pythagoras Theorem

AC^{2}=AY^{2} +YC^{2}

step 1

Find the length YC (hypotenuse of the right triangle YBC)

Applying the Pythagoras Theorem

YC^{2}=YB^{2} +BC^{2}

substitute the given values

YC^{2}=6^{2} +15^{2}

YC^{2}=261

YC=\sqrt{261}\ units

step 2

Find the shortest distance from A to C

AC^{2}=AY^{2} +YC^{2}

substitute the given values

AC^{2}=8^{2} +\sqrt{261}^{2}

AC^{2}=325

AC=\sqrt{325}\ units

AC=5\sqrt{13}\ units

8 0
3 years ago
Find the value of x and y in the parallelogram below.
Delicious77 [7]
In a parallelogram, the opposite angles are equal and the sum of the angles is 360 degrees.

W = Z and Y = X
3y = 3x
Y = X = y
3y + y + 3x + x = 360
3x + x + 3x + x = 360
8x = 360
x = 360/8 = 45

Therefore, x = 45; y = 45
7 0
3 years ago
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