Ask question

Ask question

All categories

2 years ago

13

Read and choose the correct words for the blank that match the image. (1 point) A cook using pepper on food cooking in a pan Me

gusta ________ en la comida.
A) la papa
B) el tomate
C) la pimienta
D) la carne

1 answer:

spayn [35]2 years ago

8 0

Answer:

C) la pimienta

Step-by-step explanation:

You might be interested in

2. What is the equation of the line that passes through points (-8,3/2) and (-12, 5/2)

MissTica

Answer:

y=2x+17.5

Step-by-step explanation:

17.5=35/2

7 0

7 months ago

The sum of the digits of a three-digit number is 6. The hundreds digit is twice the units digit, and the tens digit equals to th

EleoNora [17]

A+b+c=6, a=2c, b=a+c using a and b in the first equation gives you:

2c+a+c+c=6 now use a=2c again

2c+2c+c+c=6

6c=6

c=1, since a=2c

a=2, since b=a+c

b=3

So the number is 231.

6 0

2 years ago

A ball is thrown vertically in the air with a velocity of 95 ft/s. The ball is at a height of 120 ft.

sattari [20]

Answer:

The ball is at a height of 120 feet after 1.8 and 4.1 seconds.

Step-by-step explanation:

The statement is incomplete. The complete statement is perhaps the following "A ball is thrown vertically in the air with a velocity of 95 ft/s. What time in seconds is the ball at a height of 120ft. Round to the nearest tenth of a second."

Since the ball is launched upwards, gravity decelerates it up to rest and moves downwards. The position of the ball can be determined as a function of time by using this expression:

$y = y_{o} + v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}$

Where:

$y_{o}$ - Initial height of the ball, measured in feet.

$v_{o}$ - Initial speed of the ball, measured in feet per second.

$g$ - Gravitational constant, equal to $-32.174\,\frac{ft}{s^{2}}$ .

$t$ - Time, measured in seconds.

Given that $y_{o} = 0\,ft$ , $v_{o} = 95\,\frac{ft}{s}$ , $g = -32.174\,\frac{ft}{s^{2}}$ and $y = 120\,ft$ , the following second-order polynomial is found:

$120\,ft = 0\,ft + \left(95\,\frac{ft}{s} \right)\cdot t +\frac{1}{2}\cdot \left(-32.174\,\frac{ft}{s^{2}} \right) \cdot t^{2}$

$-16.087\cdot t^{2} + 95\cdot t -120 =0$

The roots of this polynomial are, respectively:

$t_{1} \approx 4.075\,s$ and $t_{2} \approx 1.831\,s$ .

Both roots solutions are physically reasonable, since $t_{1}$ represents the instant when the ball reaches a height of 120 ft before reaching maximum height, whereas $t_{2}$ represents the instant when the ball the same height after reaching maximum height.

In nutshell, the ball is at a height of 120 feet after 1.8 and 4.1 seconds.

8 0

2 years ago

Which choices are equivalent to the expression below? Check all that apply. 6√3

Westkost [7]

Answer:

case A. $\sqrt{18}*\sqrt{6}$

case B. $\sqrt{108}$

case E. $\sqrt{3}*\sqrt{36}$

Step-by-step explanation:

we have

$6\sqrt{3}$

we know that

$6\sqrt{3}=\sqrt{36*3}=\sqrt{108}$

<u>Verify each case</u>

case A) $\sqrt{18}*\sqrt{6}$

$\sqrt{18}*\sqrt{6}=\sqrt{18*6}=\sqrt{108}$

therefore

$\sqrt{18}*\sqrt{6}$ is equivalent to $6\sqrt{3}$

case B) $\sqrt{108}$

so

$\sqrt{108}$ is equivalent to $6\sqrt{3}$

case C) $\sqrt{3}*\sqrt{6}$

$\sqrt{3}*\sqrt{6}=\sqrt{18}$

therefore

$\sqrt{18}$ is not equivalent to $6\sqrt{3}$

case D) $\sqrt{54}$

so

$\sqrt{54}$ is not equivalent to $6\sqrt{3}$

case E) $\sqrt{3}*\sqrt{36}$

$\sqrt{3}*\sqrt{36}=\sqrt{108}$

therefore

$\sqrt{3}*\sqrt{36}$ is equivalent to $6\sqrt{3}$

case F) $108$

so

$108$ is not equivalent to $6\sqrt{3}$

6 0

2 years ago

What is 5 + 5 + 5 + 5 + 6 + 7 + 5 + 6 + 4 + 4+ 4 + 6+ 3 + 3 + 1 + 9?

elena-14-01-66 [18.8K]

Answer:

5,555,675,644,463,319

Step-by-step explanation:

plz mark brainly

JK 78 LOL

7 0

2 years ago

Read 2 more answers