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3 years ago

The points (2,4) and (-2,-4) are plotted on a coordinate plane the equation is y = a * x what is A?

Mathematics

1 answer:

laila [671]3 years ago

5 0

A equals to 2.

Step-by-step explanation:

y = mx + c is the equation of the line and m is the slope and c is the y- intercept.

In the given equation, y = ax , a is the slope.

Slope A can be found by means of the formula, and using the points (2,4) and (-2-4)

slope, A = (y₂ -y₁) / (x₂-x₁)

Plugin the values as,

A = (-4-4) / (-2-2) = (-8) / (-4) = 2

So the value of A is 2.

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Are the expressions equivalent? 10(x + 2); 10x + 5

lutik1710 [3]

Answer: yes, indeed it is i forgot how it is but it is

7 0

3 years ago

Arithmetic sequences please see photo

damaskus [11]

Answer:

1, yes add one, 2, no, 3, yes, you add 10. 4, no, 5, yes, you add 2.

Step-by-step explanation:

1 add one, 3 add 10 5 add 2.

Your welcome :)

4 0

3 years ago

The can shown has a diameter of 3 inches and a height of 5 inches. Find the lateral surface area of the can.

beks73 [17]

Answer:

Lateral surface area of can = 47 inch² (Approx.)

Step-by-step explanation:

Given:

Diameter of given can = 3 inches

Height of given can = 5 inches

Find:

Lateral surface area of can

Computation:

Radius of can = 3 / 2 = 1.5 inch

Lateral surface area of can = Lateral surface area of cylinder

Lateral surface area of cylinder = 2πrh

Lateral surface area of can = 2πrh

Lateral surface area of can = 2(3.14)(1.5)(5)

Lateral surface area of can = 47.1

Lateral surface area of can = 47 inch² (Approx.)

6 0

3 years ago

If the temperature after 4.4 degree drop was -2.5 degrees Celsius what was the temperature at noon

Lostsunrise [7]

Answer:

1.9°C

Step-by-step explanation:

Let X be the temperature at noon and -2.5°C be the current temperature after the drop.

-We calculate temperature at noon as:

$\bigtriangleup =t_o-t_n\\4.4=X--2.5\\\\X=4.4-2.5\\\\=1.5\textdegree C$

Hence, the temperature at noon was 1.9°C

5 0

3 years ago

Plzzzzzzzzz help meeeeeeeeeeeeee

zzz [600]

Answer:

Solution; x = - 2, x = 5

Step-by-step explanation:

We are given the following equation 2x^2 + 2x + 12 = 3x^2 - x + 2;

2x^2 + 2x + 12 = 3x^2 - x + 2 ⇒ Subtract 2 from either side,

2x^2 + 2x + 10 = 3x^2 - x ⇒ Add x on either side,

2x^2 + 2x + 10 = 3x^2 ⇒ Subtract 3x^2 on either side, simplifying result,

- x^2 + 3x + 10 = 0 ⇒ Factor out common term - 1,

- ( x^2 - 3x - 10 ) = 0 ⇒ Break expression into groups,

- ( x^2 + 2x ) + ( - 5x - 10 ) = 0⇒ Factor x from x^2 + 2x , and - 5 from - 5x - 10,

- ( x( x + 2 ) ) - 5( x + 2 ) = 0 ⇒ Factor out common term x + 2,

- ( x + 2 )( x - 5 ) = 0 ⇒ Apply Zero Factor Principle,

x + 2 = 0, and x - 5 = 0 ⇒ Simplify,

Solution; x = - 2, x = 5

7 0

3 years ago