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cricket20 [7]
3 years ago
9

Compare 5/12 and 7/12 by comparing them to a benchmark fraction on the number line

Mathematics
1 answer:
aivan3 [116]3 years ago
6 0
Compare it to 1/2 (which is the same as 6/12)
You might be interested in
A 6 foot tall man makes a shadow that is 3 1/2 feet long. How tall is a building that makes a 14 7/8 foot shadow?
timurjin [86]
C

6/3.5 = 14.875/x

6 x 14.875 = 89.25

89.25/3.5 = 25.5
7 0
3 years ago
Ziv's taxicab ride cost $33. He left a 15% tip.
Oksi-84 [34.3K]

Answer:

37.95

Step-by-step explanation:

33 x 15%

0.15 x 33 = 4.95

33 + 4.95 = 37.95

3 0
3 years ago
The lengths of the sides of a triangle are in the extended ratio 5:8:9. The perimeter of the triangle is 88 cm. What are the len
Nutka1998 [239]

Answer:

24

28

36

Step-by-step explanation:

6 0
3 years ago
How do you do this problems?
rewona [7]

x = 6

Step-by-step explanation:

It's based on similarity of triangles

DEF ~ △XYZ

\implies \mathsf{ \frac{DE }{ XY } =  \frac{EF}{YZ} =  \frac{ FD}{ZX}}

The sides should be taken in order, like the triangles start with DE and XY so, we'll proportionate DE and XY and then the next two sides and so on.

I'm using \mathsf{ \frac{DE }{XY } =  \frac{EF}{YZ} }to get the value of x.

[You can use any two fractions out of the three given above. ]

\implies \mathsf{ \frac{10}{x - 1} =  \frac{8}{4}  }

\implies \mathsf{ \frac{10}{x - 1} =  2  }

\implies \mathsf{ 10 =  2 (x - 1) }

\implies \mathsf{ 10 =  2 x - 2 }

\implies \mathsf{ 10  + 2=  2 x  }

\implies \mathsf{ 1 2=  2 x  }

\implies \mathsf{ x = 6 }

Hence, the value of x is 6.

5 0
3 years ago
If f(x) = x + 4 and g(x)=x^2-1, what is m(g o f)(x)?
Andreas93 [3]

Until now, given a function  f(x), you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given  f(x) = 2x + 3, you could find f(y2 – 1) by plugging y2 – 1 in for x to get f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1.

In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of (x, y) points:

Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and  

let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.  

 

Find (i) f (1), (ii) g(–1), and (iii) (g o f )(1).

(i) This type of  exercise is meant to emphasize that the (x, y) points are really (x, f (x)) points. To find  f (1), I need to find the (x, y) point in the set of (x, f (x)) points that has a first coordinate of x = 1. Then f (1) is the y-value of that point. In this case, the point with x = 1 is (1, –1), so:

8 0
3 years ago
Read 2 more answers
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