Ask question

Ask question

All categories

2 years ago

10

0.6(10m-5n) do you know this

1 answer:

DIA [1.3K]2 years ago

5 0

0.6*10m=6m 0.6*5n=3n rewrite 6m-3n
hope this helps have a nice nite

You might be interested in

Choose Yes or No to tell if each statement is true.

polet [3.4K]

Yes, yes, yes, yes all of them are yes hope this helps also not a genius so be careful with the answers

4 0

2 years ago

Read 2 more answers

Solve:<br>p+ 7- 5= -10 - 3<br>please use an explanation so I know how to do this next time pleaasee

skelet666 [1.2K]

Answer:

P = - 15

Step-by-step explanation:

P+7-5 = -10 - 3

P +2 = - 13

(If taking from one side,you must do to the other to get P alone.)

P+2 = - 13

-2 = - 2

The positive 2, minus the negative 2 cancels each other out, now we must subtract 2 from our other side. - 13 - 2 = - 15

P = -15

7 0

3 years ago

UT bisects WV. WV = ? <br><br> A. SV<br><br> B. 2(SV)<br><br> C. UT<br><br> D. none of the above

ValentinkaMS [17]

2(sv) is the answer for the question

4 0

3 years ago

Verify by substitution whetherthe given functions are solutions of the given DE. Primes denote derivatives with respect to x.y!!

julia-pushkina [17]

Complete Question

The complete question is shown on the first uploaded

Answer:

$y_1$ is not a solution of the differential equation

$y_2$ is not a solution of the differential equation

$y_3$ is not a solution of the differential equation

Step-by-step explanation:

The differential equation given is $y'' + y' = cos2x$

Let consider the first equation to substitute

$y_1 = cosx +sinx$

$y_1' = -sinx +cosx$

$y_1'' = -cosx -sinx$

So

$y_1'' - y_1' = -cosx -sinx -sinx +cosx$

$y_1'' + y_1' = -2sinx$

So

$-2sinx \ne cos2x$

This means that $y_1$ is not a solution of the differential equation

Let consider the second equation to substitute

$y_2 = cos2x$

$y_2' = -2sin2x$

$y_2'' = -4cos2x$

So

$y_2'' + y_2' = -4cos2x-2sin2x$

So

$-4cos2x-2sin2x \ne cos2x$

This means that $y_2$ is not a solution of the differential equation

Let consider the third equation to substitute

$y_3 = sin 2x$

$y_3' = 2cos 2x$

$y_3'' = -4sin2x$

So

$y_3'' + y_3' = -4sin2x - 2cos2x$

So

$-4sin2x - 2cos2x \ne cos2x$

This means that $y_3$ is not a solution of the differential equation

6 0

2 years ago

An object is launched at 9.8 meters per second (m/s) from a 308.7-meter tall platform. The function that represents the object's

Sedaia [141]

this is the full answer for you're Q

please give me good

8 0

2 years ago