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3 years ago

Using Quadratic Equations to Solve Problems:

Mathematics

1 answer:

satela [25.4K]3 years ago

3 0

Answer:

Step-by-step explanation:

Let x represent the number. The problem statement tells us ...

10x² = 40x

x = 4 . . . . . . . divide by 10x

the number is 4. Hope that helps love!

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Simplify the equation and show work!!!!

snow_tiger [21]

Step-by-step explanation:

This is the correct answer.

Even according to calculator and working.

So not quite sure why those options are incorrect?

4 0

2 years ago

Sir Isaac Newton wrote the equation (d=1/2 gt^2 to determine the distance (d), in meters, an object falls in a given amount of t

qwelly [4]

Answer:

D) 32g

Step-by-step explanation:

$\displaystyle d=\frac{1}{2}gt^2\\\\d=\frac{1}{2}g(8)^2\\\\d=32g$

3 0

2 years ago

In the diagram below, the circle has a radius of 25 inches. the area of the unshaded is 500pi in^2Determine and state the degree

Dmitriy789 [7]

$72^{\circ}$

1) In this question, we are going to make use of the formula for the area of that sector, to find the central angle.

2) So, let's write it out an expression involving the area of a circle, the unshaded area, and the shaded one and then plug into that the given data:

$\begin{gathered} A=\frac{\alpha}{360^{\circ}}\times\pi r^2 \\ A_{Unshaded}+A_{shaded}=A_{Circle} \\ 500\pi+\frac{\alpha}{360}\times\pi r^2=\pi r^2 \\ \\ 500\pi+\frac{α}{360}\pi25^2=25^2\pi \\ \\ 500\pi+\frac{125\piα}{72}=625\pi \\ \\ 500\pi +\frac{125\pi α}{72}-500\pi =625\pi -500\pi \\ \\ \frac{125\pi α}{72}=125\pi \\ \\ \frac{72\times \:125\pi α}{72}=72\times \:125\pi \\ \\ \frac{125\pi α}{125\pi }=\frac{9000\pi }{125\pi } \\ \\ α=72^{\circ} \\ \\ \end{gathered}$

Thus, the centra angle of that shaded area is 72º

6 0

1 year ago

Where will her cut be located? Round to the nearest tenth. Genevieve is cutting a 60-inch piece of ribbon into a ratio of 2:3. S

Maksim231197 [3]

Answer:

25.2 in

Step-by-step explanation:

The short piece will have a length that is 2/(2+3) = 2/5 of the entire usable length. The usable length is 60-2 = 58 inches long, so the cut will be ...

(2/5)(58 in) = 23 1/5 in

from the beginning of the usable part. Since the usable part of the ribbon starts 2 inches in, the cut will be 23 1/5 + 2 = 25 1/5 inches from the frayed end of the ribbon.

3 0

3 years ago

Read 2 more answers

Easy 10 poinsWhat is the volume of this composite solid willl give brainliest

vaieri [72.5K]

78m I believe is the answer

3 0

3 years ago