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anastassius [24]
3 years ago
8

2 0,484,163 expanded form

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
4 0
20,000,000+400,000+80,000+4,000+100+60+3
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It me again I need help
9966 [12]

Answer:

85%

Step-by-step explanation:

He  hit it 17/20

We want that as a percent

Multiply by 5/5

17/20*5/5 = 85/100

Percent means out of 100

85%

3 0
3 years ago
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What is the area of the slice of pie that was cut, rounded to the nearest hundredth?
krok68 [10]
To find the area of the slice of pie, you will represent the part of the pie as 37/360 because this is the fractional part that was cut.  Multiply this by the total area of the circle to get the area of this one slice.

A = 37/360 x pi x r^2
       37/360 x 3.14 x 17.5^2
A = 98.8 square feet

The approximate area of the slice was 98.8 square feet.  That is one big pie!!
5 0
4 years ago
13 14<br> x<br> 7 11<br> What is 13/7 times 14/11 equal
Ostrovityanka [42]

Answer:

(2 × 7 × 13) / (7 × 11) =

((2 × 7 × 13) ÷ 7) / ((7 × 11) ÷ 7) =

(2 × 7 ÷ 7 × 13)/(7 ÷ 7 × 11) =

(2 × 1 × 13)/(1 × 11) =

(2 × 13)/11 =

26/11;

Step-by-step explanation:

6 0
3 years ago
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A) how many men have a waist measurement of more than 85 cm
KATRIN_1 [288]

Answer:

(a)29

(b)91cm

(c)13cm

Step-by-step explanation:

(a)From the graph, 11 men have a waist measurement of 85cm and below.

Since the cumulative frequency is 40

Number of men who have a waist measurement of more than 85 cm

=40-11\\=29

(b)Median

\text{Median}=\dfrac{N}{2}\\N=40\\Median=\dfrac{40}{2}=20th$ item

Tracing 20 from the y-axis to the x-axis, the median waist measurement is 91cm.

(c)Interquartile Range

Interquartile Range = Q_3-Q_1

Q_1=\dfrac{N}{4}=\dfrac{40}{4}=10th$ item

From the graph, at y=10, x=84 cm

Q_3=\dfrac{3N}{4}=\dfrac{3*40}{4}=30th$ item

From the graph, at y=30, x=97 cm

Therefore:

Interquartile Range=97-84=13cm

5 0
3 years ago
Find the measurement of the exterior 1
irina1246 [14]

Answer:

Sorry, but I can't see this well! I am on lapton, and it is impossible to tilt the whole thing over.

6 0
3 years ago
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