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Blizzard [7]
3 years ago
6

Which rule yields the dilation of the figure STUV centered at the origin?

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

I'm a little unsure about this one, but I believe that scale factor is the rule that yields dilution, as it specifies how the diluted figure is placed on the graphing plane.

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Using this number cube and spinner, which simulation would help you answer this question?
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Solve the system of equations using the tables below
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What is 7x5+9(2x9)2+3(8+6)5-=___?
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4 years ago
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Ivan and Tanya share £150 in the ratio 4: 1<br>Work out how much more Ivan gets compared to Tanya.​
Anastasy [175]

Answer:

Ivan got £90 more than Tanya.

Step-by-step explanation:

Ivan and Tanya share the amount £150 in the ratio of 4 : 1

Amount received by Ivan = 150\times \frac{4}{(4+1)}

                                          = 150\times \frac{4}{5}

                                          = £120

Similarly, amount received by Tanya = 150\times \frac{1}{(4+1)}

                                                             = £30

Difference in their amounts = 120 - 30

                                              = £90

Therefore, Ivan got £90 more than Tanya.                                                                                                        

7 0
3 years ago
stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n
Anon25 [30]

Given functions are

s(n)=2(1.1)^n+5_{}d(n)=4(1.08)^n+3

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

t(n)=s(n)+d(n)

t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)

t(n)=2(1.1)^n+5+4(1.08)^n+3

t(n)=2(1.1)^n+4(1.08)^n+5+3

t(n)=2(1.1)^n+4(1.08)^n+8

Taking 2 as common, we get

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

Hence The total number of ducks and swans in the lake after n months is

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

8 0
1 year ago
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