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masha68 [24]
3 years ago
14

Solve the inequality 2c/3+1>7

Mathematics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

c > 9

Step-by-step explanation:

(2c/3) + 1 > 7     subtract 1 from both sides

2c/3 > 7 -1

2c/3 > 6  (multiply both sides by 3)

2c > 6(3)

2c>18    (divide both sides by 2)

c > 18 / 2

c > 9

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4 years ago
If 15 chocolates cost $11 then how much will one chocolate cost​
mina [271]

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8 0
3 years ago
Suppose that time spent on hold per call with customer service at a large telecom company is normally distributed with a mean µ
lana66690 [7]

Answer:

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.    

Step-by-step explanation:

We are given the following information in the question:

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Standard Deviation, σ = 2.5 minutes

Sample size, n = 25

We are given that the distribution of  time spent is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{2.5}{\sqrt{25}} = 0.5

P(sample mean is between 7.8 and 8.2 minutes)

P(7.8 \leq x \leq 8.2)\\\\ = P(\displaystyle\frac{7.8 - 8}{0.5} \leq z \leq \displaystyle\frac{8.2-8}{0.5})\\\\ = P(-0.4 \leq z \leq 0.4})\\\\= P(z < 0.4) - P(z < -0.4)\\\\= 0.6554 -0.3446= 0.3108

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.

4 0
4 years ago
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