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masha68 [24]
3 years ago
14

Solve the inequality 2c/3+1>7

Mathematics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

c > 9

Step-by-step explanation:

(2c/3) + 1 > 7     subtract 1 from both sides

2c/3 > 7 -1

2c/3 > 6  (multiply both sides by 3)

2c > 6(3)

2c>18    (divide both sides by 2)

c > 18 / 2

c > 9

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Answer: (3) f(8) = g(8)

<u>Step-by-step explanation:</u>

Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4

<u>      f(x)       </u>                      <u>      g(x)        </u>            <u>Comparison</u>

f(x) = 2x - 3                     g(x)=\dfrac{3}{2}x+1

f(0) = 2(0) - 3                     g(0)=\dfrac{3}{2}(0)+1

      = -3                                   = 1                     f(0) < g(0)

f(2) = 2(2) - 3                     g(2)=\dfrac{3}{2}(2)+1

     = 1                                      = 4                     f(2) < g(2)

f(8) = 2(8) - 3                     g(8)=\dfrac{3}{2}(8)+1

     = 13                                   = 13                     f(8) = g(8)

f(4) = 2(4) - 3                     g(4)=\dfrac{3}{2}(4)+1

      = 5                                   = 7                       f(4) < g(4)


The only statement provided that is true is f(8) = g(8)




3 0
3 years ago
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