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GarryVolchara [31]
4 years ago
10

Anyone can tutor a GED student

Mathematics
1 answer:
Tom [10]4 years ago
6 0

Answer:

Hi, as far as 'tutoring' goes, you can just ask any question on here, and someone will answer it and help you out as best they can!

You might be interested in
What does a rhombus look like
Elanso [62]
A rhombus is a four-sided shape where all four sides are equal length. A square is an example of a rhombus, but not all rhombuses are squares, since if you squish two of the corners inward on the square so that it's more long and skinny diagonally, then it's still a rhombus as long as the sides are of the same length.
Hope that helped =)
8 0
4 years ago
Read 2 more answers
The number of times that students go to the movies per year has mean is a normal distribution with a mean of 17 with standard de
antiseptic1488 [7]

Answer:

53.84% probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a sample of size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 17, \sigma = 8, n = 10, s = \frac{8}{\sqrt{10}} = 2.53

What is the probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times?

This probability is the pvalue of Z when X = 18 subtracted by the pvalue of Z when X = 14. So

X = 18

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18 - 17}{2.53}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 14

Z = \frac{X - \mu}{s}

Z = \frac{14 - 17}{2.53}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170

0.6554 - 0.1170 = 0.5384

53.84% probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times.

3 0
3 years ago
The list below shows all of the possible outcomes for flipping four coins.
djverab [1.8K]

Answer:

Each one has two possibilites, so the total is 2*2*2*2 = 16

Step-by-step explanation:

TTTT

TTTH

TTHT

TTHH

THTT

THTH

THHT

THHH

HTTT

HTTH

HTHT

HTHH

HHTT

HHTH

HHHT

HHHH

If you eliminate the duplicates, ie, the coins are identical, you get 4

TTTT

TTTH

TTHH

THHH

HHHH

5 0
3 years ago
Find the value of x in each case:
Zanzabum

Answer:

x=30\°

Step-by-step explanation:

<u>Find the measures of interior angles in each triangle</u>

Triangle BGC

m

The measures of triangle BGC are 90\°-60\°-30\°

Triangle CGH

we know that

m -----> by consecutive interior angles

we have that

m

so

m

m

substitute

m

we have

m

m

m

remember that

m

60\°+2x+180\°-4x=180\°

60\°=2x

x=30\°

The measures of triangle CGH are 60\°-60\°-60\°

Triangle GHE

m< EGH=90\°-2x=90-2(30\°)=30\°

m< GHE=4x=4(30\°)=120\°

remember that

m

substitute and solve for m<GEH

30\°+120\°+m

150\°+m

m

The measures of triangle GHE are 30\°-120\°-30\°

6 0
4 years ago
Read 2 more answers
Please help with both of them. Thank you!
Sveta_85 [38]

Answer:

1. B

2. D

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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