How do I "undo" multiplication
2 answers:
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Answer: 
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write
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Explanation:
The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.
So that's how I got (x is between -4 and 5; inclusive of both endpoints)
Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"
Writing is the set-builder notation way of expressing the domain. The 
portion means "x is a real number"
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write
------------------------------------------------------------------------------
Explanation:
The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.
So that's how I got
Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"
Writing
Answer:
a. From the origin, move back 3 units and down 4 units
Step-by-step explanation:
Given:
The coordinates of a point in a 3-dimensional space is given as:
(-3, -4, 0)
The value of 'x' = -3
The value of 'y' = -4
The value of 'z' = 0
At the origin, the values of 'x', 'y', and 'z' are each equal to 0.
So, the coordinates of origin is (0, 0, 0). In order to reach the point (-3, -4, 0) from the point (0, 0, 0), we don't move along the z-axis as the 'z' value remains the same. We need to move along the 'x' and 'y' directions only.
Now, 'x' is equal to -3. Negative values of 'x' occur backwards from origin. So, we move back by 3 units. to reach the point (-3, 0).
Now, the value of 'y' is -4. Negative values of 'y' occur below the origin. So, we move down by 4 units to reach the point (-3, -4).
Therefore, the correct option is option (a)
A graph in 2 dimensional is shown in support of the answer.
Answer:
The correct option is 4. Neither A nor B represents a function.
Step-by-step explanation:
The given sets of ordered pairs are
A set of ordered pairs represents a function if there exist unique outputs for all inputs. It means for each values of x there exist, a unique value of y.
In set A the value of y-coordinates are -5 and 7 at .
At x=8, there exist more than one value of y, so the set A is not a function.
In set B the value of y-coordinates are -4 and -2 at .
At x=7, there exist more than one value of y, so the set B is not a function.
Therefore neither A nor B represents a function and option 4 is correct.