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Gre4nikov [31]
4 years ago
11

How do you write 16x-3y=3 in slope intercept form

Mathematics
2 answers:
serg [7]4 years ago
6 0
Y=16/3 x -1

First, you minus both sides by 16x. This will get you -3y = 3 - 16x

Then, you divide both sides by -3. Hence on the right hand side you will get 3 - 16x over -3, which can be split into (-16x/-3) + (3/-3). By simplifying this you can get 16/3 x - 1.
SIZIF [17.4K]4 years ago
6 0

To get slope intercept form we just solve for y

16x - 3y = 3

subtract 16x from both sides

-3y = -16x + 3

divide both sides by -3

y = (16/3) x - 1

That's the slope intercept form.  We read off the slope as 16/3 and the y intercept at (0,-1).


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