How do you write 16x-3y=3 in slope intercept form

2 answers:

6 0

Y=16/3 x -1

First, you minus both sides by 16x. This will get you -3y = 3 - 16x

Then, you divide both sides by -3. Hence on the right hand side you will get 3 - 16x over -3, which can be split into (-16x/-3) + (3/-3). By simplifying this you can get 16/3 x - 1.

SIZIF [17.4K]3 years ago

6 0

To get slope intercept form we just solve for y

16x - 3y = 3

subtract 16x from both sides

-3y = -16x + 3

divide both sides by -3

y = (16/3) x - 1

That's the slope intercept form. We read off the slope as 16/3 and the y intercept at (0,-1).

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Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$