Your answer would be A
He had 6 dogs
4x6d=24
F(x)=5x^2 Has minimum (0,0)
g(x) = f(x) + 2 Shifts the graph two units up, then the minimum is 2+0=2.
h(x) = g(x+4) Shifts the graph four units left, then the minimum is at 0-4 = -4.
Then h(x) = 5(x+4)^2 + 2 has the minimum (-4,2)
And p(x) = -5(x+4)^2 + 2 has the maximum (-4,2)
Answer:
i cannt see it
Step-by-step explanation:
Sure this question comes with a set of answer choices.
Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.
Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant. This is, the equation has the form:
y = a(x + 4)(x - 2)
Now, since the point (6,10) belongs to the parabola, you can replace those coordintates to get:
10 = a (6 + 4) (6 - 2)
Therefore, any of these equivalent equations can be solved to determine the value of a:
10 = a 6 + 40) (6 -2)
10 = a (10)(4)
10 = 40a
