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3 years ago

Trig help please!!! This is due tomorrow. If you don’t mind could you please explain how you do it

Mathematics

1 answer:

vivado [14]3 years ago

8 0

Answer:

The larger acute angle is equal to 50.8 degrees.

Step-by-step explanation:

Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.

A = cos^-1 (2√6/2√15)

However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,

A = cos^-1 (2√90/30) = 50.768 degrees.

B = sin^-1 (2√90/30) = 39.231 degrees.

Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.

cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.

If you have any questions on where I got a formula or any step, feel free to ask in the comments!

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Answer:

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Step-by-step explanation:

Given

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See attachment

Required

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So;

$\angle 3 =\angle 2 = 60$

$\angle 6 =\angle 2 = 60$

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