solution:
a score of 92 has z score of
z=\frac{x-μ}{σ}=\frac{92-71}{5}=1.40
a score of 688 has z score of
z=\frac{x-μ}{σ}=\frac{688-493}{150}=1.30
a score of 92 is better because its z score is higher
Answer:
0.7233
Step-by-step explanation:
We want to find the area between the z-scores z=-0.95 and z=1.25.
We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.
For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.
This gives P(z<-0.95)=0.1711
Similarly the area to the left of z=1.25 is
P(z<1.25)=0.8944
Now the area between the two z-scores is
P(-0.25<z<1.25)=0.8944-0.1711=0.7233
If there’s a total of 210 fruit trees, and each tree produces 590 pounds a year, you multiply both those numbers and get 123,900 pounds a year.
F(y) = y + y^2 - 3
f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1
f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9
f(0) = 0 + 0^2 - 3
f(0) = -3
f(2) = 2 + 2^2 - 3
f(2) = 2 + 4 - 3
f(2) = 3
f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17
Answer:
The playground is 160ft by 360ft.
The model is 4in by 9in
First, 1ft = 12 inches.
Then the measures of the playground, in inches, is:
160*12in = 1920 in
360*12in = 4320in
The playground is 1920in by 4320in.
Then, the ratios between the measures of the playground and the model are:
1920in/4in = 480
4320in/9in = 480
This means that each inch in the model, represents 480 inches in the actual playground.
