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3 years ago

F( y ) = y + y 2 - 3

1 answer:

7 0

F(y) = y + y^2 - 3

f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1

f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9

f(0) = 0 + 0^2 - 3
f(0) = -3

f(2) = 2 + 2^2 - 3
f(2) = 2 + 4 - 3
f(2) = 3

f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17

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Andreas93 [3]

Answer:

EF is equal to 6.

Step-by-step explanation:

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3 years ago

Determine if the triangles, ΔUVW and ΔBAC, are similar. If so, identify the similarity criterion.

alexandr402 [8]

Answer:

B). SAS similarity.

Step-by-step explanation:

In Δ WVU & ΔCAB,

UV/CA = 17/34 = 1/2

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2 years ago

The following information was collected on 20 randomly chosen high school students, which compared their IQ score to musical apt

Mashcka [7]

Answer:

Y = 0.4925X - 22.26 ;

(-12.413, 13.398) ;

Yes, there is

Step-by-step explanation:

X = IQ Score ; Y = musical aptitude

The regression equation from the table given using the slope and intercept coefficient :

Y = 0.4925X - 22.26

0.4925 = slope ; Intercept = - 22.26

The 95% confidence interval of the slope :

Confidence interval = b ± Tcritical*SE

Tcritical at 95%, df = n - 2 = (20 - 2) = 18

Tcritical = 2.1009

b = slope Coefficient = 0.4925

S.E = 6.143

Hence, we have :

Confidence interval = 0.4925 ± (2.1009 * 6.143)

Confidence interval = 0.4925 ± 12.9058287

Lower boundary = 0.4925 - 12.9058287 = - 12.413

Upper boundary = 0.4925 + 12.9058287 = 13.398

(-12.413, 13.398)

There is a significant relationship between IQ score and musical aptitude because, 0 is within the confidence interval obtained.

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3 years ago

What’s the answer for 7 X WHEN x = 29 ??

kirza4 [7]

In this case, we'll have to carry out several steps to find the solution.

Step 01:

data:

Step 02:

We must analyze the equation to find the solution.

x = 29:

7 (29) = 203

The answer is:

203

7 0

1 year ago