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4 years ago

F( y ) = y + y 2 - 3

1 answer:

7 0

F(y) = y + y^2 - 3

f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1

f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9

f(0) = 0 + 0^2 - 3
f(0) = -3

f(2) = 2 + 2^2 - 3
f(2) = 2 + 4 - 3
f(2) = 3

f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17

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3 years ago

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4 years ago

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5.Solve the system using substitution.

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OK first convert one of the equations into Y=MX+b form

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3 years ago

3. if kx² + 2x + k = -kx have equal roots, find the values of k.

crimeas [40]

Answer:

k = - $\frac{2}{3}$ , k = 2

Step-by-step explanation:

Using the discriminant Δ = b² - 4ac

The condition for equal roots is b² - 4ac = 0

Given

kx² + 2x + k = - kx ( add kx to both sides )

kx² + 2x + kx + k = 0 , that is

kx² + (2 + k)x + k = 0 ← in standard form

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(3k + 2)(k - 2) = 0 ← in factored form

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4 years ago

Simplify: x^0 y^-3 / x^2 Y^-1

natita [175]

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