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madreJ [45]
3 years ago
15

I need to know the area of this trapezoid

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
8 0

Answer:

The area is 28.

Step-by-step explanation:

A=(a+b/2)h

Plug in the numbers to get (8+6/ 2) 4 to get 28

MArishka [77]3 years ago
7 0

Answer:

28

Step-by-step explanation:

You might be interested in
If 4^(x+2) = 48 what is 4^x
ivanzaharov [21]

Answer:

3

Step-by-step explanation:

4^{(x+2)} = 48  \\  \\  {4}^{x} . {4}^{2}  = 16.3 \\  \\  {4}^{x} . \cancel {16}  = \cancel {16} .3 \\  \\  {4}^{x}  = 3

4 0
3 years ago
3x − 2y = −2
Lina20 [59]

Answer: C. -3y+14

Step-by-step explanation:

3x-2y=-2\\x+3y=14

Move 3y to ther right side.

3x-2y=-2\\x=-3y+14

So the answer is C. Because x = -3y+14.

7 0
3 years ago
Read 2 more answers
Write the x-intercept of the graph of -6x + y = 8.
Trava [24]

Answer:

x-intercept:  x = -4/3

Step-by-step explanation:

x-intercept when y = 0

-6x + 0 = 8

so

-6x = 8

x = 8/-6

x = -4/3

6 0
3 years ago
3. What is the 9th term in the following sequence? 11, 17, 23, 29, . . . (1 point) 47 53 59 65
KatRina [158]
Since the common difference is 6, we can assume that the sequence is arithmetic, with rule
T(n)=6n+5  where T(1)=11
T(9)=6(9)+5=59
5 0
4 years ago
Please help with 11c!?
Contact [7]

Answer:

"To the nearest year, it would be about 9 years"

Step-by-step explanation:

11c)

This is compound growth problem. It goes by the formula:

F=P(1+r)^t

Where

F is the future amount

P is the present (initial) amount

r is the rate of growth, in decimal

t is the time in years

Given,

P = 20,000

r = 8% = 8/100 = 0.08

F = double of initial amount = 2 * 20,000 = 40,000

We need to find t:

F=P(1+r)^t\\40,000=20,000(1+0.08)^t\\2=(1.08)^t

To solve exponentials, we can take Natural Log (Ln) of both sides:

2=(1.08)^t\\Ln(2)=Ln((1.08)^t)

Using the rule shown below we can simplify and solve:

Ln(a^b)=bLn(a)

We can write:

Ln(2)=Ln((1.08)^t)\\Ln(2)=tLn(1.08)\\t=\frac{Ln(2)}{Ln(1.08)}\\t=9.0064

To the nearest year, that would be about 9 years

5 0
3 years ago
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