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aniked [119]
3 years ago
8

Points A, B, and C are collinear and AB. AC at (n, q) and point C is located at (-3,-4). What are the values of n and q?​

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0

Answer:

the answer is -4

Step-by-step explanation:

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Find an equation of the tangent line to the hyperbola: x^2/a^2 - y^2/b^2 = 1 at the point (x0,x1)
musickatia [10]

The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1

</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)

8 0
3 years ago
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vekshin1
Part b is $638.40
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8 0
3 years ago
It's a ven dyagram question pls help
slamgirl [31]

Answer:

a) A U B = {21,23,24,25,27,29,30,31 }

b) A n C = {24,30}

Step-by-step explanation:

A {21,24,27,30}

B {21,23,25,27,29,31}

C {20,22,24,26,28,30,32}

a) A U B = {21,23,24,25,27,29,30,31 }

b) A n C = {24,30}

5 0
3 years ago
What are the solutions for x when y is equal to 0 in the following quadratic
Scrat [10]

Answer: Option C

Step-by-step explanation:

Given the quadratic equation y = x^2 - 13x, substitute y=0:

 0 = x^2 - 13x

In this case, to find the solutions of the given quadratic equation, you must factor out the variable "x". Then:

0=x(x-13)

Therefore, you get that the solutions of this equation are the following:

x=0\\\\\\x-13=0\\x=13

Then, the answer is:

x = 0\ or\ x = 13

This matches with the option C.

5 0
3 years ago
17/21- (3/7 + 2/7) please answer quick
adoni [48]

Answer:

2/21

Step-by-step explanation:

17/21 -(3/7 + 2/7)

First you add

=17/21 - (5/7)

Then you want to subtract

=2/21

8 0
3 years ago
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