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Levart [38]
3 years ago
8

The roots of the equation 2x^2+8x-7=-2 are?

Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0
<span>2x^2+8x-7=-2
</span><span>2x^2+8x - 5 = 0

using the formula:- x = [-8 +/- sqrt(8^2 - 4*2*-5) ]  / 4
                                  =  -2 +/- sqrt 104)/2
                                  = 0.5495 ,   -4.549
</span>
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What is the slope of all lines perpendicular to the line y=(2/3)x+7
Alexandra [31]

Answer:

The slope is -3/2

Step-by-step explanation:

<u>A line that is perpendicular to another has the slope that has the sign reversed and is the reciprocal. </u>

Example:  Find the line perpendicular to y = 3x

First, you flip the sign which makes 3 into -3

Next, you make the reciprocal which makes -3 into <u>-1/3 </u>

Problem:  Find the line perpendicular to y = (2/3)x + 7

First, you flip the sign which makes 2/3 into -2/3

Next, you make the reciprocal which makes -2/3 into <u>-3/2</u>

Answer:  The slope is -3/2

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Step-by-step explanation:

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Solve the following triangle in which given sides are<br> a=7 b=7 c=9
blagie [28]
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.

A=B
Method 1:

We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5

B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º  ⇒ C=2*40º=80º

Answer:
a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º

Method 2:
Law of cosines:
a²=b²+c²-2bcCosA  ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º

B=A=50º

A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º

Answer:

</span>a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º</span>

8 0
3 years ago
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Answer:

curtiss can buy 7 pounds of pistachios

Step-by-step explanation:

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5 0
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