Answer:
Three ways to increase the value of variable are given below. To eleborate the answer, I am taking a variable x that need to be increase.
- x=x+1
- x++
- x+=1
Explanation:
There are three ways to increase the value of variable.
1. x= x+1
In this case, each time value of x (variable) is incremented and stored in that variable. This equation increase the value of x by 1 each time. For Example
if x=1
then in first iteration
x= x+1 = 2;
If we want to increase the value of x by more than 1, we can add that value with x, as x+2, x+3 and so on.
2. x++
This will increment the value of x by 1. If we use this equation multiple time in program, each time it will increase 1 in value of x.
3. x+=1
This also works same as equation 1. It will increment 1 in this form and can be changed with 2, 3 and so on.
Answer:
A
Explanation:
It's A Guess, Please Don't Judge Of I'm Wrong Just Tell Me.
Answer:
#include <iostream>
using namespace std;
int main() {
int n,*p;
cin>>n;//taking input.
*p=n;//passing the address of n to pointer.
cout<<*p<<endl;//printing the number using the dereferncing operator.
return 0;
}
Explanation:
The above written program in in C++.This program takes input of the integer n and stores the address of the integer in the pointer p. For printing the value of the to which the pointer is pointing we need to used the dereferencing operator * .
Answer:
The Font Tool
Explanation:
Both Calibri and Arial are default fonts, thus changing from calibri to arial requires the font tool
Private.
From the lack of information in the question, it can be assumed that the message arrived in a timely fashion.
As it is not said that the message is urgent, it is not sensitive to a reply.
Finally, there is a caveat to the message in that it is only intended for he recipient, therefore it is not a normal message.
This leaves one answer and one only: Private.