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Len [333]
3 years ago
8

Which of the following is NOT a component of a DFD?

Computers and Technology
1 answer:
OverLord2011 [107]3 years ago
3 0

Answer:

Relationship between external entities

Explanation:

There are four primary components in all data flow diagrams: entity, process, data store and data flow.

  • External entity

Also recognized as performers, sources or sinks, and terminators, internal entities generate and consume information flowing between the diagramming entity and system. These data flows are the DFD's inputs and outputs.

  • Datastore

No activities are generated by a data store, but it merely maintains data for subsequent access. Data stores may consist of long-term files or a batch of documents stored for a short time while waiting for processing.

  • Dataflow

Dataflow between external entities, procedures and information shops is depicted by an arrow symbol indicating the flow direction.

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3.6 Code Practice Question:

Write a program to input 6 numbers. After each number is input, print the biggest of the number entered so far:

Answer:

nums = []

biggest = 0

for i in range(6):

    num = int(input("Number: "))

    nums.append(num)

    if(i == 0):

         print("Largest: "+str(nums[0]))

         biggest = nums[0]

    else:

         if nums[i]>biggest:

              print("Largest: "+str(nums[i]))

              biggest = nums[i]

         else:

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Explanation:

This question is answered using python

This line declares an empty list

nums = []

This line initalizes the biggest input to 0

biggest = 0

This iteration is perfoemed for 6 inputs

for i in range(6):

This prompts user for input

    num = int(input("Number: "))

This appends user input to the list created

    nums.append(num)

For the first input, the program prints the first input as the largest. This is implemented in the following if condition

<em>     if(i == 0):</em>

<em>          print("Largest: "+str(nums[0]))</em>

<em>          biggest = nums[0]</em>

For subsequent inputs

    else:

This checks for the largest input and prints the largest input so far

<em>          if nums[i]>biggest:</em>

<em>               print("Largest: "+str(nums[i]))</em>

<em>               biggest = nums[i]</em>

<em>          else:</em>

<em>               print("Largest: "+str(biggest))</em>

<em />

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Answer:

See Explanation

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