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3 years ago

15

A rectangle is 25 in. long and 13 in. wide. What is the area of the rectangle? Enter your answer in the box as a fraction in sim

plest form. [ ] in2

1 answer:

Anarel [89]3 years ago

6 0

I hope this helps you

Area=length ×width

Area=25×13

Area =325

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among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play

kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0

3 years ago

A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A. We are interested in determining wh

mafiozo [28]

Answer:

a. 1.44

Step-by-step explanation:

We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%.

At the null hypothesis, it is tested if the proportion is of at most 40%, that is:

$H_0: p \leq 0.4$

At the alternative hypothesis, it is tested if the proportion is of more than 40%, that is:

$H_1: p > 0.4$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that $p = 0.4, \sigma = \sqrt{0.4*0.6}$

A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A.

This means that:

$n = 200, X = \frac{90}{200} = 0.45$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.45 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}$

$z = 1.44$

Thus the correct answer is given by option a.

8 0

3 years ago

I WILL GIVE BRAINLIST

docker41 [41]

I’m pretty sure it’s true

8 0

3 years ago

The vertex of the parabola is at the point (2,-5). which of the equations below could be the one for this parabola?

timofeeve [1]

Hello,
Answer is Dsince y=k(x-2)²-5 and if k=1 ==>D.

7 0

3 years ago

Read 2 more answers

Identify the factor terms by grouping: 5x3 – 4x2 + 20x – 16

jek_recluse [69]

Answer:

The answer is D

Step-by-step explanation:

All you have to do is distribute.

x^2(5x-4)+4(5x-4) =

5x^3-4x^2+20x-16

7 0

3 years ago