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statuscvo [17]
3 years ago
5

Target sells 24 bottles of water for$3 and 36 bottles of water for$4 which is the better by and how much

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

Answer:

13.............

Step-by-step explanation:


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Domain and range of the inequality y<√x+3 +1
Margaret [11]

The domain of the given inequality is y>1.

<h3>What is Inequality?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Here, given inequality:

              y < \sqrt{x+3}+1

Related equation:

             y = \sqrt{x+3}+1

The equation defined as,

    x+3 > 0

    x > -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

    \sqrt{x+3} \geq 0

adding 1 on both sides, we get

  \sqrt{x+3} + 1 \geq  1

      y ≥ 1

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

Thus, the domain of the given inequality is y>1.

Learn more about Inequality from:

brainly.com/question/20383699

#SPJ1

6 0
1 year ago
What is 48,148 in expanded form?
irina1246 [14]

Answer:

4 ten thousands, 8 thousands, 1 hundred, 4 tens, 8 ones.

Step-by-step explanation:

6 0
2 years ago
Please help and show work<br>​
Mkey [24]

x=0=>0^{5} +32 = ( 0 +2 ) ^ 5

P/s:    0^5+32=32 , (0+2)^5=2^5 =32

x=-2=> (-2)^5 + 32 = ( -2 +2 )^5

P/s:    (-2)^5 +32 = -32+32=0, (-2+2)^5=0^5=0

ok done. Thank to me :>

7 0
2 years ago
23. The Central Limit Theorem states that: (a) if n is large then the distribution of the sample can be approximated closely by
emmasim [6.3K]

Answer:

(c) if n is large, then the sampling distribution of the sample mean can be approximated closely by a normal curve.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample mean, with a large sample size, can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

This is valid no matter the shape of the population.

So the correct answer is:

(c) if n is large, then the sampling distribution of the sample mean can be approximated closely by a normal curve.

5 0
3 years ago
y varies jointly as x and z. y equals 80y=80 when x equals 5x=5 and z equals 4z=4. Find y when x equals 4x=4 and z equals 6z=6.
Lubov Fominskaja [6]
\bf \qquad \qquad \textit{direct proportional variation}\\\\&#10;\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\

\bf \textit{\underline{y} varies jointly as \underline{x} and \underline{z}}\implies y=kxz&#10;\\\\\\&#10;\textit{we also know that }&#10;\begin{cases}&#10;y=80\\&#10;x=5\\&#10;z=4&#10;\end{cases}\implies 80=k(5)(4)\implies 80=20k&#10;\\\\\\&#10;\cfrac{80}{20}=k\implies 4=k\qquad thus\qquad \boxed{y=4xz}\\\\&#10;-------------------------------\\\\ if~\begin{cases}&#10;x=4\\&#10;z=6&#10;\end{cases}~\textit{what is \underline{y}?}\qquad y=4(4)(6)
7 0
3 years ago
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