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3 years ago

How to convert 108 km/ h to m/seconds? Please show the steps.

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

8 0

Answer:

108 kilometers per hour = 30 meters per second

So, 108 kilometers per hour = 108 × 0.27777777777778 = 30 meters per second.

Airida [17]3 years ago

4 0

Answer:

distance in km / h = 108 km/h

distance in m/s = 108×1000/60×60

=108000/60×60

= 108000/3600

= 30 m/s

Step-by-step explanation:

Hope it helps . If it is wrong so , sorry for this .

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65+55x <=200 solve the inequality

fomenos

Answer:

Step-by-step explanation:

55x<=200-65

55x<=135

x<=135\55

x<=2.46

7 0

3 years ago

Read 2 more answers

Number 30 try to help

AlekseyPX

Answer:

4.5 gallons *this could be wrong*

Step-by-step explanation:

3 0

2 years ago

If K is the midpoint of JL, JK=9x-1 and KL=2x+27, find JL.

ratelena [41]

Answer:

The answer is B. 70

Step-by-step explanation:

First, since K is the midpoint of line segment JL, JK must equal KL.

So, set 9x-1 = 2x+27 and solve.

7x=28 so x=4

Then, since they are asking for JL, using x=4, add together JK and KL.

So, 9x-1+2x+27 = 11x+26 = 11(4) + 26 = 44+26 = 70

3 0

3 years ago

3 friends went to a coffee shop. Each of them got a muffin and two cups of coffee. The total cost of the order was $21.75. If a

Pavlova-9 [17]

Answer:I think it’s 3.25(3)+6c=$21.75, I’m not sure

Step-by-step explanation:

6 0

3 years ago

Crash testing evaluates the ability of an automobile to withstand a serious accident. A simple random sample of 12 small cars we

morpeh [17]

Answer:

The 95% confidence interval for the difference between proportions is (-0.046, 0.713).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (small cars), of size n1=12 has a proportion of p1=0.6667.

$p_1=X_1/n_1=8/12=0.6667$

The sample 2, of size n2=15 has a proportion of p2=0.3333.

$p_2=X_2/n_2=5/15=0.3333$

The difference between proportions is (p1-p2)=0.3333.

$p_d=p_1-p_2=0.6667-0.3333=0.3333$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{8+5}{12+15}=\dfrac{13}{27}=0.4815$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.4815*0.5185}{12}+\dfrac{0.4815*0.5185}{15}}\\\\\\s_{p1-p2}=\sqrt{0.0208+0.0166}=\sqrt{0.0374}=0.1935$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.1935=0.3793$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.3333-0.3793=-0.046\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.3333+0.3793=0.713$

The 95% confidence interval for the difference between proportions is (-0.046, 0.713).

8 0

3 years ago