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3 years ago

HELP ME PLEASE I REALLY NEED HELP PLEASE PLEASE PLEASE Thank you so much

Mathematics

2 answers:

AleksandrR [38]3 years ago

6 0

Answer:

7.8%

Step-by-step explanation:

Neko [114]3 years ago

3 0

Answer:

Assuming this is simple interest, and not compound interest, here is the answer.

30000 x 0.065 x (12 - 10) = 3900

So the answer is F, $3900

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a. About how much does a textbook weigh? b. About how much does a car weigh? c. About how much does a mosquito weigh? d. About h

Oksana_A [137]

Answer:

a. About 0.907185 kg to 2.72155 kg

b. About 1857 kg

c. About 0.005 g

d. About 0.75 feet

e. About 15 to 16 feet

Step-by-step explanation:

These are all estimated measurements and may vary across different regions and jurisdictions.

6 0

3 years ago

What is the difference of the fractions? Use the number line to help find the answer.

rjkz [21]

hope that this answers your problem !

To solve this question, we first need to layout the equation

-2 1/2 -(-1 3/4)

Step 1

-2 1/2-(-1 3/4) ... Equation

Step 2

5/2-(-1 3/4) ... Converted to improper fraction

Step 3

5/2-(-7/4) ... converted to improper fraction

Step 4

5/2--7/4 ... Got rid of parenthesis

Step 5

-3/4 ... Subtract

Answer:

-3/4 ... Answer

So the answer for this problem is C, -3/4

4 0

3 years ago

How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

$(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n$

$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

$\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)$

Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

$y=x^n\implies y'=nx^{n-1}$

4 0

4 years ago

A grocery store sells a bag of 5 oranges for $3.10. If Ishaque spent $2.48 on oranges, how many did he buy?

frozen [14]

4 Oranges, 310 divided by 5= 64, 64 times 4=248.

6 0

3 years ago

The side lengths of a triangle are 12, 15, and 10 square root 3. Classify the triangle.

Sonbull [250]

Answer: Scaline?

Step-by-step explanation:

5 0

3 years ago