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Daniel [21]
3 years ago
7

Which symbol correctly compares the two fractions?

Mathematics
2 answers:
dedylja [7]3 years ago
4 0

Answer:

5/12<3/6

Step-by-step explanation:

3/6 is 1/2 and 5/12 is smaller than 1/2

Helen [10]3 years ago
3 0

Answer:

5/12 < 3/6

Step-by-step explanation:

3/6 is equivalent to 6/12 because 3 times 2 is 6 and 6 times two is 12. 6 (the new numerator of 3/6) is greater than the numerator of 5/12- 5. 5<6. They have the same denominator so 5/12< 6/12 which is the same as 5/12 < 3/6. Hope that helped!

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What is the graph of 4x - 3y = 12?<br><br> urgents please graph
Harlamova29_29 [7]

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Solve the equation for x. the square root of the quantity x plus 4 end quantity minus 7 equals 1
HACTEHA [7]

Answer:

<h2>x = 60</h2>

Step-by-step explanation:

I hope it helps :)

\sqrt{x+4} -7=1\\\mathrm{Add\:}7\mathrm{\:to\:both\:sides}\\\sqrt{x+4}-7+7=1+7\\\sqrt{x+4}=8\\\mathrm{Square\:both\:sides}\\\left(\sqrt{x+4}\right)^2=8^2\\x+4=64\\x = 64-4\\x = 60

3 0
3 years ago
7/8 - 5/12 ayudaaa por favor es para mañana​
RUDIKE [14]
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3 0
3 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state
Rus_ich [418]

Answer:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The proportion estimated would be:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

3 0
3 years ago
Read 2 more answers
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