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Daniel [21]
3 years ago
7

Which symbol correctly compares the two fractions?

Mathematics
2 answers:
dedylja [7]3 years ago
4 0

Answer:

5/12<3/6

Step-by-step explanation:

3/6 is 1/2 and 5/12 is smaller than 1/2

Helen [10]3 years ago
3 0

Answer:

5/12 < 3/6

Step-by-step explanation:

3/6 is equivalent to 6/12 because 3 times 2 is 6 and 6 times two is 12. 6 (the new numerator of 3/6) is greater than the numerator of 5/12- 5. 5<6. They have the same denominator so 5/12< 6/12 which is the same as 5/12 < 3/6. Hope that helped!

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How many buttons are found on a simple calculator? It is measured in the _____.
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Answer: The minimum is 16, probably arranged in 4 rows of 4 buttons.


Step-by-step explanation: just grab a calculator lol



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3 years ago
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HELP! I put the formula but I don’t know the radius
ahrayia [7]

Answer:

C. 8,624

Step-by-step explanation:

recall that the formula for circumference is

Circumference = 2πr  ( = given as 85 meters)

hence,

85 = 2πr

r = 85/(2π)

given h = 15m

volume of cylinder

= πr²h

= π (85/2π)² 15  (using calculator and assuming π = 3.14)

= 8628.58

Comparing with the choices, the closest choice (within rounding error) is C. 8,624

8 0
4 years ago
What is the volume of this rectangular prism?(HURRY)
Sonbull [250]

Answer:

295.2

Step-by-step explanation:

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3 years ago
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My teacher won't help i I actually want to learn this can you please help me​
Reika [66]
15 you have to do all the steps thank it this I think
6 0
3 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
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