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Burka [1]
3 years ago
8

Select the only true statement from the following. Question 17 options: Opposite numbers have the same sign and are the same dis

tance from zero. Opposite numbers have different signs but are the same distance from zero. Opposite numbers have different signs and are different distances from zero. Opposite numbers have the same sign but are different distances from zero
Mathematics
1 answer:
Brut [27]3 years ago
8 0

Answer:

The true statement is "Opposite numbers have different signs but are the same distance from zero."

Some examples of opposite numbers are 1 and -1, 6 and -6, and 10 and -10.

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Bingel [31]
4/7 = 8/14 = 12/21 = 16/28, etc
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3 years ago
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What is the area of the base in the figure below? A cylinder with height 12 and diameter 6.
Naya [18.7K]

Answer:

About 28.27.

Step-by-step explanation:

To figure out the area of the base, you just use the formula to find the area of a circle. Which is;

A = r^2 * pi

(r stands for radius)

3 0
3 years ago
An electronics company produces​ transistors, resistors, and computer chips. Each transistor requires 3 units of​ copper, 1 unit
padilas [110]

Answer:

An electronics company can be produce 350 transistors and 340 computer chips, they can´t produce resistors.

Step-by-step explanation:

1. We will name the variables for transistors, resistors and the computer chips.

a = Transistors

b= Resistors

c = Computer chips

2. We propose three linear equations, one for the copper, one for the zinc and one for the glass.

\left \{ {{3a+3b+2c=1730} \atop {a+2b+c=690}}\atop {2a+b+2c=1380}} \right.

3. We write the matrix form as Ax=d

A=\left(\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right)

x=\left(\begin{array}{ccc}a\\b\\c\end{array}\right)

A=\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)

With this formula the solution of x is x=\frac{d}{A} or x=A^{-1}d

4. We will find the inverse matrix A^{-1} using the formula:

A^{-1} = \frac{1}{detA} (C_{A})^{T}

a. det A

det A=\left[\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right] =3*(4-1)-3*(2-2)+2*(1-4)=9-0-6=3

b. (C_{A})^{T}

C_{A}=\left(\begin{array}{ccc}4-1&.(2-2)&1-4\\-(6-2)&6-4&-(3-6)\\3-4&-(3-2)&6-3\end{array}\right)

C_{A}=\left(\begin{array}{ccc}3&.0&-3\\-4&2&3\\-1&-1&3\end{array}\right)

(C_{A}) ^T=\left(\begin{array}{ccc}3&0&-3\\-4&2&3\\-1&-1&3\end{array}\right)^T

(C_{A}) ^T=\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)

c.A^{-1}

A^{-1}=\frac{1}{3} \left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)

5. As x=\frac{d}{A} or x=A^{-1}d, the solution of x is:

x=\frac{1}{3}\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)

x=\frac{1}{3}\left(\begin{array}{ccc}(3*1730)+(-4*690)+(-1*1380)\\(0*1730)+(2*690)+(-1*1380)\\(-3*1730)+(3*690)+(3*1380)\end{array}\right)

x=\frac{1}{3}\left(\begin{array}{ccc}1050\\0\\1020)\end{array}\right)

X=\left[\begin{array}{ccc}350\\0\\340\end{array}\right]

<u><em>Therefore:</em></u>

<u><em>a= 350 Transistors</em></u>

<u><em>b=0 Resistors</em></u>

<u><em>c=340 Computer chips</em></u>

4 0
3 years ago
What is the algebraic expression for the difference between seven times a number and three times that number"?
bogdanovich [222]

Answer:

the last one

Step-by-step explanation:

6 0
3 years ago
Evaluate for the given value of the variable 1/2 X s for s = 3/10
Pani-rosa [81]
Just plug in the equation, 1/2*3/10 and multiply it out. Thus, 1*3=3 and 2*10=20
and the answer is 3/20.
8 0
3 years ago
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