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kiruha [24]
3 years ago
14

Need some help I do not necessary want the answer but the process to get the answer, thank you.

Mathematics
1 answer:
Phoenix [80]3 years ago
7 0

Given function :f(x) = 2x^3 + x^2-3x + 1.

We need to find the average rate of change from x = −2 to x = 0.

Let us find the values of y-coordinates for x=-2 and x=0 for the given function on the graph.

f(-2) = 2(-2)^3 +(-2)^2-3(-2) + 1=-5

f(0)=\:2\left(0\right)^3\:+\left(0\right)^2-3\left(0\right)\:+\:1 =1

Formula for average rate of change is :

f_{avg}=\frac{f(b)-f(a)}{b-a}

Plugging the values of f(a), f(b), a and b in the above formula, we get

f_{avg}=\frac{0-(-5)}{0-(-2)}  = \frac{5}{2}.

<h3>Therefore, the average rate of change from x = −2 to x = 0 is \frac{5}{2}.</h3>
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