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olya-2409 [2.1K]

3 years ago

6

What is -8? PLEASE HELP ME

2 answers:

Mrac [35]3 years ago

6 0

-8 IS A NEGATIVE INTEGER

Alborosie3 years ago

5 0

8 7 6 5 4 3 2 1 0-1 -2 -3 -4 -5 -6 -7 -8
0-8=-8
Or
4-12=-8

You might be interested in

What is the surface area of the right cylinder below?

IgorLugansk [536]

Answer:

Ok to find the surface area of this cylinder first we need the circumference to find this we do C=πd

C=3.14*18

C=56.52

now we have to multiple this by the height of two

113.04

now we have to find the area of the bottom to do this we do A=πR^2

A=3.14*81

A=254.34

multiple this by two for the two sides we get

508.68

now we add this to 113.04 we get

621.72

since I used 3.14 instead of more digits of pie we can round this up so the answer is C.

Your Welcome

BIFFY OUT!!!

8 0

2 years ago

Weary of the low turnout in student elections, a college administration decides to choose an SRS of three students to form an ad

-Dominant- [34]

Answer:

$P(ABC) = 0.110592$

$P(ABC^c) = 0.119808$

$P(AB^cC) = 0.119808$

$P(A^cBC) = 0.119808$

$P(AB^cC^c) = 0.129792$

$P(A^cBC^c) = 0.129792$

$P(A^cB^cC) = 0.129792$

$P(A^cB^cC^c) = 0.140608$

Step-by-step explanation:

Given

$P(A) = P(B) = P(C) = 48\%$

Convert the probability to decimal

$P(A) = P(B) = P(C) = 0.48$

Solving (a): P(ABC)

This is calculated as:

$P(ABC) = P(A) * P(B) * P(C)$

This gives:

$P(ABC) = 0.48*0.48*0.48$

$P(ABC) = 0.110592$

Solving (b): $P(ABC^c)$

This is calculated as:

$P(ABC^c) = P(A) * P(B) * P(C^c)$

In probability:

$P(C^c) = 1 - P(C)$

So, we have:

$P(ABC^c) = P(A) * P(B) * (1 - P(C))$

$P(ABC^c) = 0.48 * 0.48 * (1 - 0.48)$

$P(ABC^c) = 0.48 * 0.48 * 0.52$

$P(ABC^c) = 0.119808$

Solving (c): $P(AB^cC)$

This is calculated as:

$P(AB^cC) = P(A) * P(B^c) * P(C)$

$P(AB^cC) = P(A) * [1 - P(B)] * P(C)$

$P(AB^cC) = 0.48 * (1 - 0.48)* 0.48$

$P(AB^cC) = 0.48 * 0.52* 0.48$

$P(AB^cC) = 0.119808$

Solving (d): $P(A^cBC)$

This is calculated as:

$P(A^cBC) = P(A^c) * P(B) * P(C)$

$P(A^cBC) = [1-P(A)] *P(B) * P(C)$

$P(A^cBC) = (1 - 0.48)* 0.48 * 0.48$

$P(A^cBC) = 0.52* 0.48 * 0.48$

$P(A^cBC) = 0.119808$

Solving (e): $P(AB^cC^c)$

This is calculated as:

$P(AB^cC^c) = P(A) * P(B^c) * P(C^c)$

$P(AB^cC^c) = P(A) * [1-P(B)] * [1-P(C)]$

$P(AB^cC^c) = 0.48 * [1-0.48] * [1-0.48]$

$P(AB^cC^c) = 0.48 * 0.52*0.52$

$P(AB^cC^c) = 0.129792$

Solving (f): $P(A^cBC^c)$

This is calculated as:

$P(A^cBC^c) = P(A^c) * P(B) * P(C^c)$

$P(A^cBC^c) = [1-P(A)] * P(B) * [1-P(C)]$

$P(A^cBC^c) = [1-0.48] * 0.48 * [1-0.48]$

$P(A^cBC^c) = 0.52 * 0.48 * 0.52$

$P(A^cBC^c) = 0.129792$

Solving (g): $P(A^cB^cC)$

This is calculated as:

$P(A^cB^cC) = P(A^c) * P(B^c) * P(C)$

$P(A^cB^cC) = [1-P(A)] * [1-P(B)] * P(C)$

$P(A^cB^cC) = [1-0.48] * [1-0.48] * 0.48$

$P(A^cB^cC) = 0.52 * 0.52 * 0.48$

$P(A^cB^cC) = 0.129792$

Solving (h): $P(A^cB^cC^c)$

This is calculated as:

$P(A^cB^cC^c) = P(A^c) * P(B^c) * P(C^c)$

$P(A^cB^cC^c) = [1-P(A)] * [1-P(B)] * [1-P(C)]$

$P(A^cB^cC^c) = [1-0.48] * [1-0.48] * [1-0.48]$

$P(A^cB^cC^c) = 0.52*0.52*0.52$

$P(A^cB^cC^c) = 0.140608$

5 0

2 years ago

Rewrite the following equation as a function of x.

Alborosie

Answer:

f(x) = - x/2 + 7/2

Step-by-step explanation:

hope this helps

8 0

2 years ago

If you had a rubik's cube with 10 little squares on each side, and peeled off the outer layer, how many little cubes would you e

Pachacha [2.7K]

There is 6 sides in a cube, multiplying we get the number of squares:
6*10 = 60 little squares.
Peeling off one layer means subtracting 10 squares from the above numbers like this:
60 - 10 = 50.

Answer: we end up with 50 littles squares.

7 0

3 years ago

Read 2 more answers

7(g + 2h)<br> What is an equivalent expression

nika2105 [10]

Answer:

7g+14h

Step-by-step explanation:

hope it helped you

5 0

1 year ago

Read 2 more answers