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DanielleElmas [232]
3 years ago
13

Paul has a pocket full of 150 coins containing pennies, nickels and dimes. If 24% of his coins are pennies, and 51 of his coins

are nickels, how many dimes does he have?​
Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:He has 63 dimes

Step-by-step explanation:

Hope this helps!

24% of 150=36

51+36=87

150-87=63

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802.06 expanded form
saveliy_v [14]

in expanded form, it would be 800+2+0.6

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3 years ago
If shape 1 is similar to shape Il and shape II is similar to shape III, what does that mean for shape I and shape III?
blagie [28]

Answer:

Step-by-step explanation:

They are also similar.

Both have 4 right angles. Both have 2 sets of parallel lines. Both have 4 equal sides.  

But I think you are supposed to answer if figure 1 is similar to figure 2 and figure two is similar to figure 3 then by the transitive property, figure 1 is similar to figure 3.

7 0
3 years ago
How do you do this question?
Lena [83]

Step-by-step explanation:

The Taylor series expansion is:

Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!

f(x) = 1/x, a = 4, and n = 3.

First, find the derivatives.

f⁽⁰⁾(4) = 1/4

f⁽¹⁾(4) = -1/(4)² = -1/16

f⁽²⁾(4) = 2/(4)³ = 1/32

f⁽³⁾(4) = -6/(4)⁴ = -3/128

Therefore:

T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!

T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³

f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0.  So we can eliminate the top left option.  That leaves the other three options, where f(x) is the blue line.

Now we have to determine which green line is T₃(x).  The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).

The bottom right graph is the only correct option.

3 0
3 years ago
Answer the following ratios <br><br> 55 paise to Rs 1<br> 500ml to 2 liters
AfilCa [17]
55:1

500:2

There ya go!
7 0
3 years ago
Complete the point slope equation of the line through (-5, 7) and (-4, 0).​
IgorLugansk [536]

For this case we have that by definition, the point-slope equation of a line is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points:

(x_ {1}, y_ {1}): (- 5,7)\\(x_ {2}, y_ {2}): (- 4,0)

We found the slope:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} =  \frac {0-7} {- 4 - (- 5)} = \frac {-7} {-4 + 5} = \frac {-7} {1} = - 7

Thus, the equation is of the form:

y = -7x + b

We substitute one of the points and find "b":

0 = -7 (-4) + b\\0 = 28 + b\\b = -28

Finally, the equation is:

y = -7x-28

Answer:

y = -7x-28

5 0
3 years ago
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