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3 years ago

Find the percent of decrease from 340 to 150. Round to the nearest tenth of a percent if necessary.

Mathematics

1 answer:

Ad libitum [116K]3 years ago

8 0

well, from 340 down to 150, their difference is 190.

now, if we take 340 to be the 100%, what is 190 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 340&100\\ 190&p \end{array}\implies \cfrac{340}{190}=\cfrac{100}{p}\implies p=\cfrac{190\cdot 100}{340}\implies p\approx 55.88$

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Can you help me find the volume base area latera area and total area please to this problem

krek1111 [17]

Answer:

BA = 25π,

LA = 25√2π,

TA = 25π + 25√2π,

V = 41 and 2 / 3π

Step-by-step explanation:

We need to determine the height here, as it is not given, and is quite important to us. The height is a perpendicular line segment to the radius, hence forming a 45 - 45 - 90 degree triangle as you can see. Therefore, by " Converse to Base Angles Theorem " the height should be equal in length to the radius,

( Height = 5 inches = Radius

______

Now knowing the height, let's begin by calculating the base area. By it's name, we have to find the area of the base. As it is a circle, let us apply the formula " πr^2 "

$\pi r^2\\= \pi ( 5 )^2\\= 25\pi$ - Base Area = 25π

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The lateral area is simply the surface area excluding the base area, the surface area having a formula of " πr^2 + πrl. " Thus, the lateral area can be calculated through the formula " πrl, " but as we are not given the slant height ( l ) we have to use another formula, $l= \sqrt{r^2+h^2}$ -

$\pi r( \sqrt{r^2+h^2} )\\= \pi( 5 )( \sqrt{5^2 + 5^2} )\\= 25\sqrt{2} \pi$ - Lateral Area = 25√2π

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And the surface area is the base area + lateral area -

$25\pi + 25\sqrt{2} \pi$ - Surface Area

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The volume of a cone is 1 / 3rd that of a cylinder, with a simple formula of Base * height. Therefore, we can conclude the following -

$1 / 3( 25\pi )( 5 )\\= 25 / 3( 5 )( \pi )\\= 41 \frac{2}{3}\pi$ - Volume = 41 and 2 / 3π

8 0

3 years ago

Identify the first operation needed in this equation

ruslelena [56]

Addition is the first step in solving the equation. Here is how to solve this problem:

x/3 - 3 = 11
+ 3 + 3
------------------------
x
(3) -------- = 14(3)
3

x = 42

5 0

3 years ago

Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x<6

Oksi-84 [34.3K]

Answer:

$-1/3$

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

$9x^2-15x$

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

$9x^2-15x=6$

Subtract 6 from both sides:

$9x^2-15x-6=0$

Divide everything by 3:

$3x^2-5x-2=0$

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

$3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0$

Find the x using the Zero Product Property:

$3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2$

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

$x=-1/3$

Assume that the correct symbol is >. Thus,

$x>-1/3$

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

$9x^2-15x$