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3 years ago

Write an equation in slope-intercept form for each line described passes through (−2, −6) and (4, 6)

Mathematics

1 answer:

pogonyaev3 years ago

5 0

Answer:

y=2x=5

Step-by-step explanation:

the slope of the equation is 2 and the y intercept can be anywhere between -6 and 6 so i just chose 5

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Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.

ioda

$\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }$

Solution:

From given question,

Number of pounds Jake carry = $6\frac{1}{4} \text{ pounds }$

Number of pounds his father carry is $1\frac{5}{7}$ times as much as jake

To find: Number of pounds Jake father can carry

Convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

$\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}$

Then according to question,

$\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}$

$\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }$

3 0

3 years ago

HEELLPP plss!!!!!!!! Solve

Elanso [62]

The top answer on your screen is the answer. Hope this help

6 0

3 years ago

OH NO!!! Madeleine’s data has been corrupted, again! Using the incomplete data file below, which she was able to recover from he

-Dominant- [34]

Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

∑X*∑Y =1513*2668= 4036684

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0

3 years ago

HELP ME WITH THISSS PLZZZ!!!! ahh thank youu lol

Naddik [55]

The answer is b I think

3 0

2 years ago

Can someone see if i did this correct? If not pls explain

Taya2010 [7]

Answer:

Not right.

Step-by-step explanation:

m <HGJ + m <KGJ =180°

So, m <HGJ = 180° - m <KGJ = 180° - 86° =94°

8 0

2 years ago