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stepan [7]
3 years ago
6

Write an equation in slope-intercept form for each line described passes through (−2, −6) and (4, 6)

Mathematics
1 answer:
pogonyaev3 years ago
5 0

Answer:

y=2x=5

Step-by-step explanation:

the slope of the equation is 2 and the y intercept can be anywhere between -6 and 6 so i just chose 5

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Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.
ioda

\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

<em><u>Solution:</u></em>

From given question,

Number of pounds Jake carry = 6\frac{1}{4} \text{ pounds }

Number of pounds his father carry is 1\frac{5}{7} times as much as jake

To find: Number of pounds Jake father can carry

<em><u>Convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}

<em><u>Then according to question,</u></em>

\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}

\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

3 0
3 years ago
HEELLPP plss!!!!!!!!<br><br> Solve
Elanso [62]
The top answer on your screen is the answer. Hope this help
6 0
3 years ago
OH NO!!! Madeleine’s data has been corrupted, again! Using the incomplete data file below, which she was able to recover from he
-Dominant- [34]

Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0
3 years ago
HELP ME WITH THISSS PLZZZ!!!! ahh thank youu lol
Naddik [55]
The answer is b I think
3 0
2 years ago
Can someone see if i did this correct? If not pls explain
Taya2010 [7]

Answer:

Not right.

Step-by-step explanation:

m <HGJ + m <KGJ =180°

So, m <HGJ = 180° - m <KGJ = 180° - 86° =94°

8 0
2 years ago
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