Answer:
7 times during the first 15 minutes
Step-by-step explanation:
Remember that

so

Decompose the numbers 18 and 42 in prime factors
we know that


Find the least common multiple (LCM)
The LCM is

we need to find all multiples of 126 that are less than or equal 900.

therefore
7 times during the first 15 minutes
solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
Answer:
2,304
Step-by-step explanation:
u multiply one length by it widgth so 48 x 48
<u>Given</u>:
The given expression to find the nth term of the sequence is 
The first term of the sequence is 
We need to determine the third term of the sequence.
<u>Second term:</u>
The second term of the sequence can be determined by substituting n = 2 in the nth term of the sequence.
Thus, we have;




Thus, the second term of the sequence is -40.
<u>Third term:</u>
The third term of the sequence can be determined by substituting n = 3 in the nth term of the sequence.
Thus, we have;



Thus, the third term of the sequence is 120.