Answer:
Dilate from center A by scale factor of 2, then reflect over line AC
Step-by-step explanation:
Answer:
u = 4.604 , s = 2.903
u' = 23.025 , s' = 6.49
Step-by-step explanation:
Solution:
- We will use the distribution to calculate mean and standard deviation of random variable X.
- Mean = u = E ( X ) = Sum ( X*p(x) )
u = 1*0.229 + 2*0.113 + 3*0.114 + 4*0.076 + 5*0.052 + 6*0.027 + 7*0.031 + 8*0.358.
u = 4.604
- Standard deviation s = sqrt ( Var ( X ) = sqrt ( E ( X^2) + [E(X)]^2
s = sqrt [ 1*0.229 + 4*0.113 + 9*0.114 + 16*0.076 + 25*0.052 + 36*0.027 + 49*0.031 + 64*0.358 - 4.604^2 ]
s = sqrt ( 8.429184 )
s = 2.903
- We will use properties of E ( X ) and Var ( X ) as follows:
- Mean = u' = E (Rate*X) = Rate*E(X) = $5*u =
u' = $5*4.605
u' = 23.025
- standard deviation = s' = sqrt (Var (Rate*X) ) = sqrt(Rate)*sqrt(Var(X)) = sqrt($5)*s =
s' = sqrt($5)*2.903
u' = 6.49
Best is to draw a sketch of the three points.
Next step is to find the distances BC, CD, DB.
The perimeter is the sum of the three distances.
The distances are found using the distance formula:
D=sqrt((y2-y1)^2+(x2-x1)^2)
order of (x1,y1), (x2,y2) is not important.
BC=sqrt((3- -3)^2+(5-3)^2)=sqrt(6^2+2^2)=sqrt(40)=5.324
CD=sqrt((-1-3)^2+(0-5)^2)=sqrt(4^2+5^2)=sqrt(41)=6.403
DB=sqrt((-3- -1)^2+(3-0)^2)=sqrt(2^2+3^2)=sqrt(13)=3.606
So perimeter = BC+CD+DB=16.333 (approximately)
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Answer:
The speed of the plane with no wind is 378 miles per hour.
Step-by-step explanation:
Since at maximum speed, an airplane travels 1680 miles against the wind in 5 hours, and flying with the wind. the plane can travel the same distance in 4 hours, to determine what is the speed of the plane with no wind, the following calculation must be performed:
Against the wind = 1680/5 = 336
With the wind = 1680/4 = 420
420 - ((420 - 336) / 2) = X
420 - 42 = X
378 = X
Therefore, the speed of the plane with no wind is 378 miles per hour.