Answer:
25
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given: 
We need to completely isolate
to solve.






Finally, multiply both sides by -2 to completely isolate
.

Answer:
35 mililiters
Step-by-step explanation:
Given

Required
Accumulated amount from t = 0 to 2
This implies that, we substitute the values of t from 0 to 2 in the function



The accumulated sand (r) is:


