The probability of one arrives within the next 10 minutes
when he already been waiting for one jour for a taxi is,
P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10)
= 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1
= 0.3679
The probability of one arrives within the next 10 minutes
when he already been waiting for one hour for a taxi is 0.3679
Alright, so you have to have heads and tails, as well as 3 spots each for each even number. Therefore, we need heads with 2 4 6 as well as tails with 2 4 6 (the third one down in the first picture)
Well the minutes are 198 still working on the rest
Answer:
3m - 5
Step-by-step explanation:
3(m - 3) + 4 Distribute the 3
3m - 9 + 4 Simplify
3m - 5
