Answer:
1) 4:7
2) 3:1
3) $0.50 per ounce
4) 7.5 degrees per hour
5) 61 mils per hour
6) 30 pounds per box
7) $1.89 per notebook
8)
a. 3 centerpieces for party per hour
b. 14 hours
m∠FDE = 52°
Solution:
Given data:
DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠ABF + m∠CBF = 180°
116° + m∠CBF = 180°
m∠CBF = 64°
If CD || BE, then CD || BF.
Hence CD || BE and BE || FD.
Therefore BFCD is a parallelogam.
<em>In parallelogram, Adjacent angles form a linear pair.</em>
m∠CBF + m∠BFD = 180°
64° + m∠BFD = 180°
m∠BFD = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠BFD + m∠DFE = 180°
116° + m∠DFE = 180°
m∠DFE = 64°
we know that DE ≅ DF.
<em>In triangle, angles opposite to equal sides are equal.</em>
m∠DFE = m∠DEF
m∠DEF = 64°
<em>sum of all the angles of a triangle = 180°</em>
m∠DFE + m∠DEF + m∠FDE = 180°
64° + 64° + m∠FDE = 180°
m∠FDE = 52°
19 = h/3 - 8
add 8 to each side
19+8 = h/3 -8 +8
27 = h/3
multiply by 3 on each side
27*3 = h/3 *3
81 = h
Answer:
Step-by-step explanation:
There are two ways to go about solving this problem, depending on your available time and fluency with the topic:
Solve it “properly”, by graphing the inequalities yourself, then comparing your graph to the available options.
Use the test-taking strategies of “ruling out answers that are clearly wrong”, followed by “use enough of what you know about the problem to select the correct answer.
Let’s walk through both, since you should be able to do both, as this problem looks very much like a practice problem for a standardized Algebra 1 test.
So! To graph a linear inequality, the steps include graphing the line, determining what type of line, and determining how it’s shaded, though the order of these steps is only important if you’re doing math in pen, which is a terrible idea.
The first inequality:
