Set up a system of equations:
2x+3y=6
x-3y=9
You can solve this with elimination by adding the two equations together:
3x+0y = 15
3x=15
x=5
Then, plug this value back into either of the original equations to find the y value:
5-3y=9
-3y=4
y= -4/3
The point of intersection is (5,-4/3)
Refer to the attached image.
As we can observe ABCD is a square, whose corners that is A,B,C and D lie on the circle.
The diameter AC = 0.35 meter.
We have to find the side of square.
Let the measure of side of a square be 'l' meter
In triangle ABC,
By Pythagoras theorem, we get





So, l = 0.25 meter
Therefore, the measure of side of the square is 0.25 meter.
Answer:
Step-by-step explanation:
6j - k = 23
6j + 3k = 11.....multiply by -1
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6j - k = 23
-6j - 3k = -11 (result of multiplying by -1)
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-4k = 12
k = -12/4
k = - 3 <=====
6j - k = 23
6j - (-3) = 23
6j + 3 = 23
6j = 23 - 3
6j = 20
j = 20/6
j = 10/3 <===
solution is : j = 10/3 and k = -3
Um what? There is no table or anything to go off of.