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3 years ago

Find the difference or type "impossible" ?

Mathematics

2 answers:

anygoal [31]3 years ago

4 0

Answer:

its 123 coding got me triiipiiing

docker41 [41]3 years ago

3 0

Answer:

Impossible

Step-by-step explanation:

You might be interested in

John has a ribbon that was 1 1/2 meters long. He used 2 pieces that were each 1/3 of that length. How much ribbon did John use?

Bond [772]

Answer:

1 meter.

Step-by-step explanation:

1 1/2 * 1/3

= 3/2 * 1/3

= 3/6

= 1/2.

So John used 2*1/2 = 1 meter of the ribbon.

5 0

4 years ago

What is the measure of \angle x∠xangle, x?<br> Angles are not necessarily drawn to scale.

GuDViN [60]

Answer:

Step-by-step explanation:

x + 149 = 180

x = 180 - 149

x = 31

Answer: 31

3 0

2 years ago

Read 2 more answers

Anybody know this? I’m not sure how to do it at all.

Crazy boy [7]

2 is 42 but i’m not sure about one

5 0

3 years ago

Read 2 more answers

In a right –angled triangle, the length of hypotenuse and shorter sides are 13 cm and 5 cm respectively. Work out the other side

stellarik [79]

Answer: The other side is 12 cm.

Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$
$a^{2} + (5)^{2} = (13)^{2}$
$a^{2} + 25 = 169$
$a^{2} = 144$
$a = \sqrt{144}$
$a = 12$

7 0

3 years ago

A parabola can be drawn given a focus of (-11, -2) and a directrix of x= -3

fgiga [73]

Check the picture below, so the parabola looks more or less like that.

now, the vertex is half-way between the focus point and the directrix, so that puts it where you see it in the picture, and the horizontal parabola is opening to the left-hand-side, meaning that the distance "P" is negative.

$\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\begin{cases} h=-7\\ k=-2\\ p=-4 \end{cases}\implies 4(-4)[x-(-7)]~~ = ~~[y-(-2)]^2 \\\\\\ -16(x+7)=(y+2)^2\implies x+7=-\cfrac{(y+2)^2}{16}\implies x=-\cfrac{1}{16}(y+2)^2-7$

8 0

2 years ago