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soldi70 [24.7K]
3 years ago
14

Gavin is building a model of a kitchen. In the model, 2/5 of the floor tiles are white, 1/2 of the floor tiles are yellow, and 1

/10 of the floor tiles are brown. How many floor tiles could be in the model?
Mathematics
2 answers:
nata0808 [166]3 years ago
5 0

Answer:

The number of tiles that could be in the model is 10

Step-by-step explanation:

Gavin is building a model of a kitchen . In the model, 2/5 of the floor tiles are white , 1/2 of the floor tiles are yellow and 1/10 of the floor tiles are brown. The number of model of the floor tiles can be computed as follows:

The fraction represented is just like the fraction of the type(color) of floor type over the number of floor tiles. The highest denominator of the fractions is 10( 1/10). The other fraction can be represented also with a denominator of 10.

2/5 can be represented as 4/10 which is 4 tiles

1/2 can be represented as 5/10 which is 5 tiles

1/10 is 1/10 since it has the highest denominator, it will represent the number of tiles that could be in the model. The brown tile is 1 tile.

The number of tiles that could be in the model is 10

AlladinOne [14]3 years ago
3 0
Answer: 10 How? 2/5= 4 tiles 1/10= 1 tile 1/2= 5 tiles Add them up and there is your answer.
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The area of the figure is 100

Step-by-step explanation:

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3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

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2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

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Multiply both sides by a:

-b=c

Here we have:

a=3

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c=-(k-6)

So we are solving

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3k-2=-(k-6)

Distribute:

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Add k on both sides:

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Add 2 on both side:

4k=8

Divide both sides by 4:

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Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
Can someone help me please
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8 0
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