Answer:
f + g)(x) = f (x) + g(x)
= [3x + 2] + [4 – 5x]
= 3x + 2 + 4 – 5x
= 3x – 5x + 2 + 4
= –2x + 6
(f – g)(x) = f (x) – g(x)
= [3x + 2] – [4 – 5x]
= 3x + 2 – 4 + 5x
= 3x + 5x + 2 – 4
= 8x – 2
(f × g)(x) = [f (x)][g(x)]
= (3x + 2)(4 – 5x)
= 12x + 8 – 15x2 – 10x
= –15x2 + 2x + 8
\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(
g
f
)(x)=
g(x)
f(x)
= \small{\dfrac{3x+2}{4-5x}}=
4−5x
3x+2
My answer is the neat listing of each of my results, clearly labelled as to which is which.
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}
C I think because the lines intercept at a common point
Hello! And thank you for your question!
First use the rule: A/b x c/d = ac/bd
3 x 2 over 5 x 3
Simplify 3 x 2:
6 over 5 x 3
Simplify 5 x 3:
6/15
Simplify further:
2/5
Final Answer:
2/5
Answer:
The given situation is in direct variation.
The dependent variable is the distance covered and the independent variable is the number of hours.
Step-by-step explanation:
We are given the following information in the question:
Steve drove 300 miles in 5 hours.
After stopping for gas, he drove an additional 120 miles in 2 hours.
We calculate the ratios and if these ratios are equal then, we can say that the situation represent a direct variation.
For direct variation, the equation is of the form y = kx that is , we can write,
To check the ratio:
Thus, the given situation is in direct variation.
The dependent variable is the distance covered and the independent variable is the number of hours.
Answer:
No answer there in the option...
Normally the two opposite numbers are -1 and 1
