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vlabodo [156]
2 years ago
12

Which is the greatest to least, 12 3/4, 12 3/5 and 12.7

Mathematics
2 answers:
maks197457 [2]2 years ago
5 0

Answer:

12.75, 12.70, 12.60

Step-by-step explanation:

12 3/4 = 12.75

12 3/5 = 12.60

12.7 = 12.70

Ne4ueva [31]2 years ago
4 0

Answer:

12 3/4, 12.7, 12/5

Step-by-step explanation:

12 3/4 = 12.75

12 3/5 = 12.6

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Hope this helps! the answer is option (A). if you still don’t understand after looking at my solution feel free to clarify ya

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15. What is the dependent and independent variable in this scenario?
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The dependent variable is 5 and the independent is 15
7 0
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$8.00+$6.00 = <br> answer
Lady bird [3.3K]

Answer:

$8.00+$3.00+$3.00=$14.00

Step-by-step explanation:

5 0
3 years ago
Hello everyone, could you please solve this problem step by step. I don't have the exact solution and there are no options for i
lara31 [8.8K]

Answer:

<em>The area of the shaded part  = 61.46</em>

<em />

Step-by-step explanation:

Assume the hypotenuse of the triangle is c (c>0)

As the triangle inscribed in the semi circle is the right angle triangle, its hypotenuse is equal to the diameter of the circle.

The hypotenuse of the triangle can be calculated by Pythagoras theorem as following: c^{2} =a^{2} +b^{2} =(2\sqrt{5}) ^{2} + (4\sqrt{5}) ^{2} = 20 + 80 = 100

=> c = 10

So that the semi circle has the diameter = 10 => its radius = 5

  • The total area of 2 semi circles is equal to the area of the circle with radius =5

    => The total area of 2 semi circles is: \pi x 5^{2} = 25\pi

  • The area of a triangle inscribed in the semi circle is: 1/2 x a x b = 1/2 x 2\sqrt{5\\ x 4\sqrt{5} = 20

    => The area of 2 triangles inscribed in 2 semi circles is: 2 x 20 = 40

  • The area of the square is: c^{2} = 10^{2} =100

It can be seen that:

<em>The area of the shaded part = The area of the square - The total area of 2 semi circles + The total are of 2 triangles inscribed in semi circles </em>

<em>= 100 -  25</em>\pi<em> + 40 = 61.46</em>

6 0
3 years ago
What are the points of inflection of k(x)=sinx-(1/4)sin2x
zalisa [80]

Answer:

Option d is correct.

Step-by-step explanation:

The point of inflection of a function y = f(x) at a pointy c is given by f''(c) = 0.

Now, the given function is

k(x) = \sin x - \frac{1}{4}\sin 2x

Differentiating with respect to x on both sides we get,

k'(x) = \cos x - \frac{1}{2} \cos 2x

Again, differentiating with respect to x on both sides we get,

k''(x) = - \sin x + \sin 2x = - \sin x + 2 \sin x \cos x

So, the condition for point of inflection at point c is

k''(c) = 0 = - sin c + 2 sin c cos c

⇒ sin c(2cos c - 1) = 0

⇒ sin c =  0 or \cos c = \frac{1}{2}

⇒ c = 0 or c = \pm \frac{\pi}{3}

Therefore, option d is correct. (Answer)

8 0
3 years ago
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