Answer:
C on Edge. 2 (square root of 53) +10 units
Step-by-step explanation:
The remaining number of flires that Linda still not posted is 40.
According to the given question.
The total number of fliers Linda have = 84
Fraction of fliers Linda posted = 1/3
And, fraction of fliers Linda posted second time from the remaning fliers = 2/7
Now,
1/3 of 84 fliers = 1/3 × 84 = 28
So, the number of fliers are left with Linda after first posting = 84 - 28 = 56
Again she posted 2/7 fliers. The number of flires Linda posted second time is given by
⇒ 2/7 × 56 = 16
Thereore, the number of fliers that Lindna still not posted = 56 - 16 = 40
Hence, Linda still not posted 40 fliers.
Find out more information about fraction and remaining numbers here:
brainly.com/question/2254581
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Area of the base = pi*(4x+2)^2 = pi*(16x^2 +16x +4)
volume of cylinder = pi*r^2 *h
V = pi *(16x^2 +16x +4)(5x+4) = pi*(80x^3 +80x^2 +20x +64x^2 +64x +16) =
= pi*(80x^3 +144x^2 +84x +16)
than we consider it without pi so result choice A. is right sure
hope helped
Answer:
The minimum number of different tanks needed to safely house all the fish is:
Step-by-step explanation:
To identify the minimum number of different tanks, we're gonna concentrate in a fish species, in this case can be the A: as you see in the table, the A species can live with all the fish excepting the F and G, by their side, the F and G can't live together , by this reason, this three species must live in a different tank, in the next form:
- Tank 1: <em>A</em>
- Tank 2: <em>F</em>
- Tank 3: <em>G</em>
Now the B species, it can live with A, F and G, but for this example we can put in the tank 1 (the tank of the A species). The C especies can live with A, F and G, but how we have A and B together, we're gonna put the C especies in the tank 3 (the tank of the G especies). The D species can live with A and G, we're gonna put in the tank 1 because can live with B species too. The E species can live with A and F, we're gonna put in the tank 2 (the tank of the F species) because the E species can't live with D that is in the in the tank 1. Al last, the H species just can live with A, E, F, and H species, by this reason, the only tank that can be put is the tank 2. In this form, the order is the next:
- Tank 1: <em>A, B, D</em>.
- Tank 2: <em>F, E, H</em>.
- Tank 3: <em>G, C</em>.
And t<u>he owner of the pet store must buy three different tanks to display these tropical fish</u>.
