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Anettt [7]
3 years ago
9

How do I find slope on a graph?

Mathematics
1 answer:
sergejj [24]3 years ago
3 0

<em><u> </u></em><em><u>WE</u></em><em><u> </u></em><em><u>CAN</u></em><em><u> </u></em><em><u>FIND</u></em><em><u> </u></em><em><u>SLOPE</u></em><em><u> </u></em><em><u>ON</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>GRAPH</u></em><em><u> </u></em><em><u>BY</u></em><em><u> </u></em><em><u>USING</u></em><em><u> </u></em><em><u>BELOW</u></em><em><u> </u></em><em><u>FORMULA</u></em><em><u> </u></em><em>:</em><em>-</em>

<em>I</em><em>f</em><em> </em><em>two</em><em> </em><em>point</em><em> </em><em>on</em><em> </em><em>graph</em><em> </em><em>are</em><em> </em><em>given</em><em>.</em>

<em>such</em><em> </em><em>that</em><em> </em><em>,</em>

<em> </em>

<em>there</em><em> </em><em>coordinates</em><em> </em><em>are</em><em> </em><em>(</em><em>x</em><em>,</em><em>y</em><em>)</em><em> </em><em>&</em><em> </em><em>(</em><em>x</em><em>'</em><em> </em><em>,</em><em>y'</em><em>)</em><em>.</em>

<em>Then</em><em>,</em><em> </em>

<em>m =  \frac{ {y}^{.}  - y}{{x}^{.}  - x}</em>

<em>#</em><em>$</em><em>#</em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u>HOPE</u></em><em><u> </u></em><em><u> </u></em><em><u>YOU</u></em><em><u> </u></em><em><u> </u></em><em><u>UNDERSTAND</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em>#</em><em>$</em><em>#</em>

<em>#</em><em>$</em><em>¥</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u>THANK</u></em><em><u> </u></em><em><u> </u></em><em><u>YOU</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em>¥</em><em>$</em><em>#</em>

<em><u>❤</u></em><em><u> </u></em><em><u>☺</u></em><em><u> </u></em><em><u>☺</u></em><em><u> </u></em><em><u>☺</u></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u>☺</u></em><em><u> </u></em><em><u>☺</u></em><em><u> </u></em><em><u>☺</u></em><em><u> </u></em><em><u>❤</u></em><em><u> </u></em>

<em><u /></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u /></em><em><u> </u></em>

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Answer:

$1,665.19

Step-by-step explanation:

Interest=PRT/100 where P is the principal amount deposited by Michelle, R is the rate offered per year in terms of percentage, T is the period in years

Substituting P for $1385, T for 7 years, R for 2.89% we obtain interest as follows

Interest=$1,385*2.89*7 years/100=$280.1855

Balance after 7 years will be the sum of principal amount and interest gained

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Rounding off to 2 decimal places

Balance=$1665.19

Therefore, Michelle's balance is $1,665.19

4 0
3 years ago
( simultaneous equations)
daser333 [38]

Answer:

See method below.

Step-by-step explanation:

m/n + n/3 = 2

2/m + n = 4    

First  eliminate the fractions by multiplying the first equation by 3n:-

3m + n^2 = 6n...........(1)

and the second equation by m:-

2 + mn = 4m..............(2)

Now we solve using substitution:-

From equation  (2):-

4m - mn = 2

m = 2 / (4 - n)

Now substitute for m in equation (1):-

6/ (4 - n) + n^2 = 6n

6 + n^2(4 - n) = 6n(4 - n)

6 + 4n^2 - n^3 = 24n - 6n^2

n^3 - 10n^2 + 24n - 6 = 0

This will not factor so we could solve this using graphical software.

To find the values of the variable m we substitute the found values of n into one of the original equations and solve for m.






6 0
3 years ago
You can afford a $1350 per month mortgage payment. You’ve found a 30 year loan at 7% interest.
Mice21 [21]
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B) 1350 because 45 x 30 = 1350


C) 7% because it’s 7% to begin with
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