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barxatty [35]
3 years ago
6

Ezra made 70% of the free throws he attempted last basketball season. If Ezra attempted 50 free throws last season, how many did

he make?
Mathematics
2 answers:
erastova [34]3 years ago
6 0
35, because if he makes 70 out of 100, you can divide that by 2 so you get 35 out of 50

Lera25 [3.4K]3 years ago
3 0
35 :) If you change the percent into a decimal (0.70) and multiply that by 50, you will get the answer!
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Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
3 years ago
(Worth 30 points) What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term
kolbaska11 [484]

Answer:

a_n=5-2(n-1), all integers where n≥1

Step-by-step explanation:

we know that

The explicit equation for an arithmetic sequence is equal to

a_n=a_1+d(n-1)

a_n is the th term

a_1 is the first term

d is the common difference

n is the number of terms

we have

a_1=5\\a_2=3

Remember that

In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference.

To find out the common difference subtract the first term from the second term

d=a_2-a_1=3-5=-2

substitute the given values in the formula

a_n=5-2(n-1)

The domain is all integers for n\geq 1

3 0
3 years ago
All of the following are true statements except _____.
soldier1979 [14.2K]

Answer:

|−93| = −93

Step-by-step explanation:

|Mode| = mode

3 0
2 years ago
What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
Adult tickets for a charity concert were $5 each. Students were admitted for $2 each. The charity concert
AfilCa [17]

Answer:

students 150

adult 550

Step-by-step explanation:

x + y = 700

5x + 2y = 3050

x = 700 - y

5(700 - y) + 2y = 3050

3500 - 5y + 2y = 3050

-3y + 3500 = 3050

-3y = 3050 - 3500

-3y = -450

y = -450 / -3

y = 150

x = 700 - y

x = 700 - 150

x = 550

3 0
3 years ago
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