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sesenic [268]
3 years ago
11

In which quadrant does the terminal side of a 118° angle lie?

Mathematics
1 answer:
user100 [1]3 years ago
3 0

<em>Answer:</em>

<em>II Quadrant</em>

<em>Step-by-step explanation:</em>

<em>Because : </em>

<em>All the angles between 0 and 90 degrees are in the</em><em> I quadrant.  </em>

<em>All the angles between 90 and 180 degrees are in the</em><em> II quadrant </em>

<em>All the angles between 180 and 270 degrees are in the </em><em>III quadrant </em>

<em>And all the angles between 270 and 360 degrees are in the </em><em>IV quadrant </em>

<em> </em>

<em>Since 118° lies between 90° and 180° degrees your answer will be :</em><em> II Quadrant</em>

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<h2>A.</h2>

So let's break down this sentence (Let n = unknown number):

  • "A number is doubled and then 1 is added to it"; Remember that double means multiplied by 2. With this sentence, we can determine that "2n + 1" is a part of the equation.
  • "The answer is divided by 5, and then increased by 16"; The "answer" they refer to is "2n + 1" from the prior sentence. Since this is divided by 5 and <em>then</em> added by 16, we can determine that \frac{2n+1}{5}+16 is a part of our equation.
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<h2>B.</h2>

Now, let's solve our prior equation found in A. To solve for the unknown number, n, we need to isolate the variable onto 1 side of the equation. Firstly subtract both sides by 16 to cancel out the + 16 on the left side:

\frac{2n+1}{5}=2

Next, multiply both sides by 5 to cancel out the division on the left side:

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<u>In short, the number is 9/2 or 4.5.</u>

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