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sesenic [268]
3 years ago
11

In which quadrant does the terminal side of a 118° angle lie?

Mathematics
1 answer:
user100 [1]3 years ago
3 0

<em>Answer:</em>

<em>II Quadrant</em>

<em>Step-by-step explanation:</em>

<em>Because : </em>

<em>All the angles between 0 and 90 degrees are in the</em><em> I quadrant.  </em>

<em>All the angles between 90 and 180 degrees are in the</em><em> II quadrant </em>

<em>All the angles between 180 and 270 degrees are in the </em><em>III quadrant </em>

<em>And all the angles between 270 and 360 degrees are in the </em><em>IV quadrant </em>

<em> </em>

<em>Since 118° lies between 90° and 180° degrees your answer will be :</em><em> II Quadrant</em>

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Can the sides of a triangle have lengths 1, 7, and 11? Explain
Airida [17]

No

Given 3 sides of a triangle, the sum of any 2 sides must be greater than the third side.

Consider the 3 given sides 1, 7 and 11

7 + 11 = 18 > 1

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1 + 7 < 11 ⇒ not valid

Hence these sides do not form a triangle


6 0
3 years ago
Find the area of each shape by decomposing each shape into rectangle and/or triangle.
avanturin [10]

Remark

You don't have to decompose the second one, and it is better if you don't. Just find the area as you probably did: use the formula for a trapezoid. You have to assume that the 6cm line hits the 2 bases at right angles for each of them, otherwise, you don't know the height. So I'm going to assume that we are in agreement about the second one.

Problem One

The answer for this one has to be broken down and unfortunately, you answer is not right for the total area, although you might get 52 for the triangle. Let's check that out.

<em><u>Triangle</u></em>

Area = 1/2 * b * h

base = 16 cm

h = 10 - 4 = 6

Area = 1/2 * 16 * 6

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Area = L * W

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3 0
3 years ago
Lesson 6 Practice Problems
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6 0
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Juliette [100K]

Answer:

If we assume that everyone in the group is an owner, we would have

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8 0
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