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4 years ago

How many 2/3 are in 3/4

1 answer:

4 0

Let's get them to have a common denominator
2/3 and 3/4 are
8/12 and 9/12
clearly 8/12 will fit in 9/12 only once
so to simplify the fractions
2/3 fits in 3/4 only once

Hope this helps :)

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Solve the inequality.

mr Goodwill [35]

Answer:

which inequality? where the question ?

Step-by-step explanation:

4 0

3 years ago

Determine and state the maximum error of the function G(x,y,z)=20 ln⁡(xyz^2 ) using differentials when (x,y,z)=(2,3,4) and given

Leona [35]

Answer:

The maximum error in the function G, ΔG = ±4

Step-by-step explanation:

G(x,y,z) = 20 In (xyz²)

Total or maximum error for a multi-variable function is given by

ΔG = (∂G/∂x) (Δx) + (∂G/∂y) (Δy) + (∂G/∂z) (Δz)

(∂G/∂x) = 20yz²/xyz² = 20/x

(∂G/∂y) = 20xz²/xyz² = 20/y

(∂G/∂z) = 40xyz/xyz² = 40/z

Δx = ±0.10

Δy = ±0.15

Δz = ±0.20

ΔG = (∂G/∂x) (Δx) + (∂G/∂y) (Δy) + (∂G/∂z) (Δz)

ΔG = (20/x) (0.10) + (20/y) (0.15) + (40/z) (0.2)

At the point (x,y,z) = (2,3,4)

ΔG = (20/2) (0.10) + (20/3) (0.15) + (40/4) (0.2) = 10(0.10) + 20(0.05) + 10(0.2) = 1 + 1 + 2 = 4

ΔG = ±4

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2

saul85 [17]

$\large\underline{\sf{Solution-}}$

Let us assume that:

$\sf \longmapsto x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ... \infty } } }$

We can also write it as:

$\sf \longmapsto x = \sqrt{6 + x }$

Squaring both sides, we get:

$\sf \longmapsto {x}^{2} =6 + x$

$\sf \longmapsto {x}^{2} - x - 6 =0$

By splitting the middle term:

$\sf \longmapsto {x}^{2} - 3x + 2x - 6 =0$

$\sf \longmapsto x(x - 3) + 2(x - 3 ) =0$

$\sf \longmapsto (x+ 2)(x - 3 ) =0$

Therefore:

$\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}$

$\sf \longmapsto x = - 2,3$

But x cannot be negative. 

$\sf \longmapsto x = 3$

Therefore, the value of the expression is 3.

$\large\underline{\sf{Verification-}}$

Given:

$\sf\longmapsto x=3$

We can also write it as:

$\sf\longmapsto x = \sqrt{9}$

$\sf\longmapsto x = \sqrt{6+3}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{9}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}$

This pattern will continue.

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}$

7 0

3 years ago

What's the answer to: 39-7x=-4(7x+7)+4

SOVA2 [1]

Simplify -28x-28+4−28x−28+4 to -28x-24−28x−24
 Add 28x28x to both sides39−7x+28x=−24Simplify 39-7x+28x39−7x+28x to 39+21x39+21x
39+21x=−24Subtract 39 from both sides
21x=−24−39Simplify -24-39−24−39 to −63
21x=−63Divide both sides by 21
x=− $\frac{63}{21}$
Simplify tex] \frac{63}{21} [/tex] to 3
x=−3

3 0

3 years ago

If Sinx= 3/4, find x (3sf)

Alenkasestr [34]

If Sinx= 3/4 ===> sin x=0.75

===> arcsin (0.75) = x

===> x=48.59°

3 0

4 years ago