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Likurg_2 [28]
4 years ago
13

On Friday there were 8 snowboarders for every 3 skiers at Slovak ski resort. On Saturday the ratio of the number of snowboarders

to the number of skiers was 4:7 there were 168 snowboarders at the ski resort on Friday there were the same number of people at the ski resort on Saturday as there were on Friday how many more skiers were there than snowboarders at the ski resort on Saturday
Mathematics
1 answer:
atroni [7]4 years ago
6 0

Answer:

There are 46 more skiers than snowboarder

Step-by-step explanation:

Given

Ratio of Snowboarders to Skiers

On Friday:

Ratio = 8 : 3

On Saturday:

Ratio = 4 : 7

Population = 168

Required

Determine the difference in the number of skiers and snowboarders on Saturday

On Saturday, we have

Ratio = 4 : 7

Calculate Total

Total = 4 + 7

Total = 11

Calculate the number of skiers

Skiers = \frac{7}{11} * 168

Skiers = \frac{1176}{11}

Skiers = 107 (Approximated)

Calculate the number of snowboarders

Snowboarders = \frac{4}{11} * 168

Snowboarders = \frac{672}{11}

Snowboarders = 61 (Approximated)

Calculate the difference

Difference = 107 - 61

Difference = 46

<em>Hence, there are 46 more skiers than snowboarder</em>

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3 years ago
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<h3>Answer:  28</h3>

==========================================================

Explanation:

Method 1

Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.

There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.

Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.

----------------------------------

Method 2

There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.

----------------------------------

Method 3

Use the nCr combination formula with n = 8 and r = 2

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There are 28 combinations possible. Order doesn't matter (eg: match-up AB is the same as match-up BA).

Notice how the (8*7)/2 expression is part of the steps shown above in the nCr formula.

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