The volume of a box is the amount of space in the box.
The expressions that can represent the length and the width are: ![\mathbf{(2x - 1)\ and\ (x + 3)}](https://tex.z-dn.net/?f=%5Cmathbf%7B%282x%20-%201%29%5C%20and%5C%20%20%28x%20%2B%203%29%7D)
The volume is given as:
![\mathbf{V(x) =2x^3 + 5x^2 - 3x}](https://tex.z-dn.net/?f=%5Cmathbf%7BV%28x%29%20%3D2x%5E3%20%2B%205x%5E2%20-%203x%7D)
Divide through by height (i.e x), to get the base area
![\mathbf{A(x) =2x^2 + 5x - 3}](https://tex.z-dn.net/?f=%5Cmathbf%7BA%28x%29%20%3D2x%5E2%20%2B%205x%20-%203%7D)
Expand
![\mathbf{A(x) =2x^2 + 6x - x - 3}](https://tex.z-dn.net/?f=%5Cmathbf%7BA%28x%29%20%3D2x%5E2%20%2B%206x%20-%20x%20-%203%7D)
Factorize
![\mathbf{A(x) =2x(x + 3) - 1(x + 3)}](https://tex.z-dn.net/?f=%5Cmathbf%7BA%28x%29%20%3D2x%28x%20%2B%203%29%20-%201%28x%20%2B%203%29%7D)
Factor out x + 3
![\mathbf{A(x) =(2x - 1) (x + 3)}](https://tex.z-dn.net/?f=%5Cmathbf%7BA%28x%29%20%3D%282x%20-%201%29%20%28x%20%2B%203%29%7D)
Hence, the expressions that can represent the length and the width are: ![\mathbf{(2x - 1)\ and\ (x + 3)}](https://tex.z-dn.net/?f=%5Cmathbf%7B%282x%20-%201%29%5C%20and%5C%20%20%28x%20%2B%203%29%7D)
Read more about volumes at:
brainly.com/question/13338592
Your answer is (z+1+w) (z+1-w)
Answer: 876
Step-by-step explanation:so all you need to do is go into
39in³ is a required volume.
Solution given:
for upper one
length[l]=8in
breadth[b] =3in
height[h]=1in
now
volume [V1]=l×b×h=8×3×1=24in³
again for lower one:
length[l]=6-1=5in
breadth[b] =3in
height[h]=1in
volume [V2]=l×b×h=5×3×1=15in³
Again
total volume =V1+V2=24in³+15in³=39in³
Answer:
y = 50
Step-by-step explanation:
y / 5 = 10
Multiply each side by 5
y/5*5 = 10*5
y = 50